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netineya [11]
3 years ago
12

Survival of the fittest

Biology
1 answer:
Natalija [7]3 years ago
7 0
What exactly is your question?
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You cross two true-breeding parents (one with yellow seeds and one with green seeds), grow and self-pollinate the F1 generation,
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Answer:

1500

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Let's assume that the allele for yellow seed color is "Y" and the allele for green seed color is "y". Genotype of pure breeding yellow seeded plant would be "YY" and that of the green seeded plant would be "yy". A cross between YY and yy gives all heterozygous yellow seeded plants (Yy) in F1 progeny. Self pollination of two F1 plants (Yy x Yy) obtains F2 generation in 3 yellow: 1 green ratio.

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Therefore, total number of yellow seeded plants in F2 progeny = 3/4 x 2000= 1500

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