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SCORPION-xisa [38]
3 years ago
11

Please help. Answer only if you know the correct answer. I’ll mark you as brainliest if correct.

Mathematics
2 answers:
zavuch27 [327]3 years ago
8 0

Answer:

37 miles an hour

Step-by-step explanation:

you set up a ratio

100/62 on left 60/x on right

cross mult and get 100x=60(62)

100x=3720

x= 37.2

aksik [14]3 years ago
7 0

Answer:

37

Step-by-step explanation:

If the speed is 100 km and is equivalent to 62 mph then 100/62 is 1.612903.

We can then divide 60 by 1.612903 to get 37

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I need help with answering the following questions. :/ :)
s344n2d4d5 [400]

Answer:

  a) (0, ∞)

  b) (-∞, ∞)

  c) x = 0

Step-by-step explanation:

It helps to have some idea what the log function is.

__

a) The domain is all positive numbers: (0, ∞).

b) The range is all real numbers: (-∞, ∞). (The vertical translation downward by 5 units does not change that.)

c) There is a vertical asymptote where the argument of the log function is zero: at x=0.

3 0
3 years ago
From where Kiana is standing, she must look up at a 50° angle to see the top of a building. If she backs up 50 feet, she will ne
Morgarella [4.7K]
For this case, what we must do is solve the following system of equations:
 tan (50) = h / x
 tan (40) = h / (x + 50)
 Solving the system we have:
 (x + 50) * tan (40) = h
 (x) * tan (50) = h
 Matching:
 (x + 50) * tan (40) = (x) * tan (50)
 Rewriting:
 x (tan (50) - tan (40)) = 50 * tan (40)
 x = 50 * tan (40) / (tan (50) - tan (40))
 x = 118.9692621
 Substituting:
 h = (x) * tan (50)
 h = (118.9692621) * tan (50)
 h = 141.7820455
 Answer:
 
The height of the building is:
 
h = 141.7820455 ft
5 0
3 years ago
Read 2 more answers
Researchers have found that after 25 years of age the average size of the pupil in a
laila [671]

Answer:

At 25 = 6.8612mm

At 50 years = 5.422mm

Step-by-step explanation:

Equation,

d = 2.115Logₑa + 13.669

d = diameter of the pupil

a = number of years

Note : Logₑa = In a (check logarithmic rule)

d = 2.115Ina + 13.669

1. At 25 years,

d = -2.115In25 + 13.669

d = -2.115 × 3.2188 + 13.669

d = -6.807762 + 13.669

d = 6.8612mm

At 25 years, the pupil shrinks by 6.86mm

2. At 50 years,

d = -2.1158In50 + 13.669

d = -2.1158 * 3.912 + 13.669

d = -8.2770 + 13.699

d = 5.422mm

At 50 years, the pupil shirks by 5.422mm

To save this question, I had to plug in the values into the equation.

Solving for Logₑa might be difficult, so instead I used Inx which is the same thing. Afterwards, i substituted in the values and solve the equation for each years.

8 0
3 years ago
A rectangle is placed around a semi circle as shown below. The width of the rectangle is 7yd. find the area of the shaded region
Nady [450]

Answer:

21.07 yd^2

Step-by-step explanation:

The width of the rectangle is also the radius of the semicircle. The length of the rectangle is 2 radii, or 14 yd.

The area of the shaded region is the same as the area of the semicircle subtracted from the area of the rectangle.

area of shaded region = area of rectangle - area of semicircle

A = LW - (1/2)(pi)r^2

A = 14 yd * 7 yd - (1/2)(3.14)(7 yd)^2

A = 98 yd^2 - (1.57)(49 yd^2)

A = 98 yd^2 - 76.93 yd^2

A = 21.07 yd^2

4 0
3 years ago
Jack bought a stereo on sale for $231 . The original price was $385 . What was the percent of decrease in a price
Alenkinab [10]
231 / 385 = 0.6        diving the price it is by the price is was gives the answer
= 60%
8 0
3 years ago
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