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marishachu [46]
2 years ago
7

Abele bought a skirt and blouse. The skirt cost $15 more than the blouse. Let b represent the cost of the blouse. Write an algeb

raic expression for cost of skirt.
Mathematics
1 answer:
julsineya [31]2 years ago
7 0
S = b + 15

s = skirt
b = blouse

The skirt is $15 more than the blouse

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Write the equation in slope form intercept m=-2(3,-1)
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y = -2x + 5

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Find b using the m and (3, -1) given by plugging them into y = mx + b

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3 years ago
A consumer group is interested in estimating the proportion of packages of ground beef sold at a particular store that have an a
snow_tiger [21]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16  

And rounded up we have that n=385

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

We assume that the estimated proportion for this case is \hat p =0.5 since we don't have prior information.

And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16  

And rounded up we have that n=385

6 0
3 years ago
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