width = w
length = w+4
Area = l*w
substitute
96 = (w+4) *w
distribute
96 = w^2 +4w
subtract 96 from both sides
0 = w^2 +4w -96
factor
0=(w+12) (w-8)
w+12=0 w-8=0
w=-12 w=8
cannot have negative width
w=8
l=12
Answer: width =8 cm
length = 12cm
Answer:
I am pretty sure it is B
Step-by-step explanation:
:)
Answer:
Given a square ABCD and an equilateral triangle DPC and given a chart with which Jim is using to prove that triangle APD is congruent to triangle BPC.
From the chart, it can be seen that Jim proved that two corresponding sides of both triangles are congruent and that the angle between those two sides for both triangles are also congruent.
Therefore, the justification to complete Jim's proof is "SAS postulate"
Step-by-step explanation:
Answer:
(6,-4)
Step-by-step explanation:
-3x-9y = 18 (equation 1)
4x+3y = 12 (equation 2)
multiply equation 2 by 3, and add it to equation 2
-3x-9y = 18
12x+9y = 36
-----------------
X's cancel out
9x = 54
Divide both sides by 9
x = 6
Plug in 6 for x in any of the original equations
(Plugging into Equation 2)
4(6)+3y = 12 Multiply 4(6)
24+3y = 12 Subtract 24 from both sides
3y = -12 Divide 3 on both sides
y = -4
Therefore the solution is (6,-4).
