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3 years ago

6

In mrs. wiggins class of 32 students, 3/8 of the student are taking French, and 1/2 of the students are taking Latin. If 6 stude

nts are taking both, how many students are taking neither?

1 answer:

Vlad1618 [11]3 years ago

5 0

The answer is 10 you see 6 people are in both of the classes so you have to subtract 6 from the 12 and 16 12+16-6=22
32-22=10

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Which is a solution for 3 > f? f = 7 f = 9 f= 3 f =2?

Fed [463]

Answer:

F = 2

Step-by-step explanation: If you want to know which one is a solution, you have to substitute the numbers in for F.

F = 7:

3 > f

3 > 7

This is false because 3 is NOT greater than 7, it is less than 7.

F = 9:

3 > f

3 > 9

This is false because 3 is NOT greater than 9, it is less than 9.

F = 2:

3 > f

3 > 2

This is TRUE because 3 IS greater than 2.

Hope this help you!!! :)

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3 years ago

How it came to this

ryzh [129]

You were really close :D
The mistake you made is that 44 - 36 is 8, not 6.
Using 8 instead, the answer is:
$3~\frac{8}{12}=3~\frac{3}{4},~or~3.75$

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3 years ago

What is the sum?

RSB [31]

It is C) 2.55 because i was taught that you can subtract the negative from the positive. 5.35-2.8=2.55 and it is positive

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3 years ago

Read 2 more answers

How do you verify this trigonometric identity? cos^2 θcot^2 θ = cot^2 θ - cos^2 θ

sattari [20]

<h3>Explanation:</h3>

Replace cos^2(θ) with 1-sin^2(θ), and cot(θ) with cos(θ)/sin(θ).

cos^2(θ)cot^2(θ) = cot^2(θ) - cos^2(θ)

(1 -sin^2(θ))cot^2(θ) = . . . . . replace cos^2 with 1-sin^2

cot^2(θ) -sin^2(θ)·cos^2(θ)/sin^2(θ) = . . . . . replace cot with cos/sin

cot^2(θ) -cos^2(θ) = cot^2(θ) -cos^2(θ) . . . as desired

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3 years ago

The weights of red delicious apples are approximately normally distributed with a mean of 9 Ounces and a standard deviation of 0

Simora [160]

Answer:

The mean of W is 55 ounces.

The standard deviation of W is 4.33 ounces.

Step-by-step explanation:

Let X: weight of a red delicious apple, and B: the weight of the box and packing material.

The distribution that will represent W: the total weight of the packaged 5 randomly selected apples will be also normally distributed.

Applying the property of the mean: $E(aX)=aE(X)$ , the mean of W will be:

$\mu_W=E(W)=E(5X+B)=5E(X)+E(B)=5*9+10=45+10=55$

Applying the property of the variance: $V(aX+b)=a^2V(X)$ , the variance of W will be:

$\sigma^2_W=V(W)=V(5X+B)=5^2V(X)+V(B)=25*0.75+0=18.75$

The mean standard deviation of W will be the squared root of V(W):

$\sigma_W=\sqrt{V(W)}=\sqrt{18.75}=4.33$

The mean of W is 55 ounces.

The standard deviation of W is 4.33 ounces.

3 0

4 years ago