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marshall27 [118]
3 years ago
13

Rajiv and his family left home on a trip and drove for 2 hours before they stopped to eat. After 1.5 hours, they were back on th

e road. They arrived at their destination 3 hours later at 5:00 P.M. What time did they leave home?
Mathematics
2 answers:
Contact [7]3 years ago
6 0
It would be 1:00 for the first one
Aliun [14]3 years ago
5 0

Answer:

The first one is 1 and the second one is 1:00

Step-by-step explanation:

e set of words that refers to the clock is: midnight (exactly 12:00 am), morning (from 12:01 am to 11:59 am), noon (exactly 12:00 pm), afternoon (from 12:01 pm to 6:00 pm), evening (from 6:00 pm to 11:59 pm).

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Meena's family took a road trip to Niagara Falls. Meena slept through the last 49% of the trip. If the total length of the trip
Daniel [21]

<u>Answer:</u> (update)

<h2>122.5 miles</h2>

<u>Explanation:</u>

given: the total length of the trip = 500 miles

hence the road's length from home to niagara falls = 500/2 = 250

Sleepy Meena missed:

250/100×49 = 2.5×49 = 122.5 miles

:)

7 0
3 years ago
Three classes of school children are selling tickets to the school play. The number of tickets sold by these classes, and the nu
Westkost [7]

Answer:

The expression for the average number of tickets sold per school child is:

M = \frac{tickets*class1 + tickets2*class2 + tickets3*class3}{class1 + class2 + class3}

Step-by-step explanation:

The average number of tickets sold per school child is the weighted mean calculus between the number of tickets sold by these classes and the number of children in each classes.

This is the multiplication between the number of tickets sold by these classes and the number of children in each classes divided by the total weight(in this exercise, the total weight is the total number of school child).

So, the expression for the average number of tickets sold per school child is:

M = \frac{tickets*class1 + tickets2*class2 + tickets3*class3}{class1 + class2 + class3}

3 0
3 years ago
Please answer this question above.
ioda
The distance between point J and line KL would be the line perpendicular to the line, which is line JM.

The answer would be B.
7 0
3 years ago
Please help me with this asap
vagabundo [1.1K]

Answer:

C

Step-by-step explanation:

3 0
2 years ago
You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta
vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }

m = -\frac{\cos 2\theta}{\sin \theta}

The tangent line is horizontal when m = 0. Then:

\cos 2\theta = 0

2\theta = \cos^{-1}0

\theta = \frac{1}{2}\cdot \cos^{-1} 0

\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right), for all i \in \mathbb{N}_{O}

\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}, for all i \in \mathbb{N}_{O}

The first four solutions are:

x:   \sqrt{2}   -\sqrt{2}  -\sqrt{2}  \sqrt{2}

y:     1        -1        1     -1

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

6 0
3 years ago
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