5 raised by 2- 5 (68-60)= (with explanation plz)
1 answer:
You might be interested in
The given data is
t, h: 0 2 4 6 8 10
r(t), L/h: 8.6 7.9 6.8 6.4 5.7 5.3
The lower and upper estimates for the total amount that leaked may be computed as the Left and Right Riemann sums.
The shape of the graph of r versus will determine which of the two sums yields an upper or lower sum.
The plot of the graph is shown below.
The Left Riemann sum is
Sl = 2*(8.6+7.9+6.8+6.4+5.7) = 70.8 L
The Right Riemann sum is
Sr = 2*(7.9+6.8+6.4+5.7+5.3) = 64.2 L
Answer:
The lower estimate for oil leakage is 64.2 L
The upper estimate for oil leakage is 70.8 L
t, h: 0 2 4 6 8 10
r(t), L/h: 8.6 7.9 6.8 6.4 5.7 5.3
The lower and upper estimates for the total amount that leaked may be computed as the Left and Right Riemann sums.
The shape of the graph of r versus will determine which of the two sums yields an upper or lower sum.
The plot of the graph is shown below.
The Left Riemann sum is
Sl = 2*(8.6+7.9+6.8+6.4+5.7) = 70.8 L
The Right Riemann sum is
Sr = 2*(7.9+6.8+6.4+5.7+5.3) = 64.2 L
Answer:
The lower estimate for oil leakage is 64.2 L
The upper estimate for oil leakage is 70.8 L
Answer:
The graph you have is wrong. This is the right graph.
Hope this helps! Have a nice day, good luck, and stay safe!
Refer to the diagram shown below.
Given:
m∠A = 19°
c = 15
By definition,
sin A = a/c
Therefore
a = c*sin A = 15*sin(19°) = 4.8835
cos A = b/c
Therefore
b = c*cos A = 15*cos(19°) =14.1828
Answer:
The lengths are 4.88, 14.18, and 15.00 (nearest hundredth)
Given:
m∠A = 19°
c = 15
By definition,
sin A = a/c
Therefore
a = c*sin A = 15*sin(19°) = 4.8835
cos A = b/c
Therefore
b = c*cos A = 15*cos(19°) =14.1828
Answer:
The lengths are 4.88, 14.18, and 15.00 (nearest hundredth)