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zimovet [89]
3 years ago
6

A new mixture of​ self-tanning & moisturizing lotions for everyday use is being developed. This mixture is made by mixing 70

0 ounces of everyday moisturizing lotion for ​$0.70 per ounce with​ self-tanning lotion worth ​$3 per ounce. If the new​ self-tanning & moisturizing lotion mixture is to cost $ 1.60 per​ ounce, how many ounces of the​ self-tanning lotion should be in the​ mixture?
Mathematics
1 answer:
777dan777 [17]3 years ago
7 0

Answer:

450 ounces

Step-by-step explanation:

We know that the cost of the mixture C_m must be the cost of the everyday moisturizing lotion C_e plus the cost of the self-tanning lotion C_s, which means C_m=C_e+C_s.

The cost of any substance will be the cost per ounce of the substance (c), multiplied by the number of ounces (n), which means C=nc, so we have from the previous formula that we have:

n_m c_m=n_e c_e + n_s c_s

But we also know that the number of ounces of the mixture must be the sum of the number of ounces of the everyday moisturizing lotion with the number of ounces of the self-tanning lotion, so we have

n_e c_e + n_s c_s=n_m c_m=(n_e+n_s) c_m=n_e c_m+n_s c_m

We want to calculate the number of ounces of the​ self-tanning lotion (n_s), so we solve for that variable:

n_e c_e + n_s c_s=n_e c_m+n_s c_m

n_s c_s-n_s c_m=n_e c_m-n_e c_e

n_s (c_s-c_m)=n_e(c_m-c_e)

n_s=\frac{n_e (c_m-c_e)}{(c_s-c_m)}

And substitute our values in this formula, to get:

n_s=\frac{(700\ ounces) (\$1.6-\$0.7)}{(\$3-\$1.6)}=450\ ounces

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