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erastovalidia [21]
3 years ago
10

If p(x)= 10x^2+10x-3, find p(-4)

Mathematics
1 answer:
PIT_PIT [208]3 years ago
4 0

Answer:

Step-by-step explanation:

What this means is when you start with P(x) you get 10^2 + 10x - 3 on the right

p(-4) has the meaning that when you see an x on the right hand side, you put in -4 for that x. Do this procedure for every x on the right.

p(-4) = 10(-4)^2 + 10(-4) - 3

p(-4) = 10*16 + (-40) - 3

p(-4) = 160 - 40 - 3

p(-4) = 120 - 3

p(-4) = 117

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The temperature fell 12°F from 46°Fto 34°F in 10 hours. how much would the temperature fall over 15 hours if the pattern continu
Stolb23 [73]
18 degrees F because 
it dropped 12 degrees=10 hours
                   x degrees=15 hours
x is what you want to find out which is how many degrees it would drop in 15 hours.
12x15 then divided by 10 is 18.
5 0
4 years ago
Find the inverse of the function f(x) = (x - 4) 2 - 5 if x ≥ 4.
Serggg [28]
Same here, we do a quick switcharoo on the variables first,

\bf \stackrel{f(x)}{y}=(x-4)^2-5\qquad inverse\implies \boxed{x}=\left( \boxed{y}-4 \right)^2-5
\\\\\\
x+5=(y-4)^2\implies \pm\sqrt{x+5}=y-4\implies \pm\sqrt{x+5}+4=y
6 0
3 years ago
Find the equilibrium point for the pair of supply and demand functions. Demand: q=18/x Supply: q=x/2
storchak [24]

Answer:

The equilibrium point is at x = 6

Step-by-step explanation:

Given

Demand (q) = \frac{18}{x}

Supply (q) = \frac{x}{2}

Required

Determine the equilibrium point

The equilibrium point is determined by

Demand = Supply

Substitute values for Demand and Supply

\frac{18}{x} = \frac{x}{2}

Cross Multiply

x * x =  18 * 2

x^2 = 36

Take positive square root of both sides

x = 6

Hence;

<em>The equilibrium point is at x = 6</em>

5 0
4 years ago
Which graph shows a linear function?
dimulka [17.4K]

Answer:

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8 0
3 years ago
In t hours the train has traveled s miles. Find the formula for v, the speed of the train (in mph) in terms of t and s. Find the
Digiron [165]

Answer:

Part 1 .

As per the given statement: In t hours the train has traveled s miles.

Distance of the train = s mile

Time = t hours

Formula for :

Speed of the train(v) = \frac{\text{Distance of the train}}{\text{Time}}

or

v = \frac{s}{t} mph           .....[1]

Substitute the value of t = 3 hours and s = 180 miles in [1], to solve for v;

v = \frac{180}{3} = 60 mph

Therefore, the speed of the train(v) is, 60 mph

Part 2.

Similarly,

The formula for speed of the train (v) is given by;

v =\frac{s}{t}

Substitute the value of t = 2.5 hours and s = 225 miles to solve for v;

v = \frac{225}{2.5} = 90 mph

Therefore, the speed of the train(v) is, 90 mph


7 0
3 years ago
Read 2 more answers
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