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erik [133]
2 years ago
8

Joannie lent $200 to her sister. Four years later, her sister repaid her in full with $228. What simple annual interest rate did

Joannie's sister pay?
A 3.0
B. 3.5
C.4.0
D.4.5

pls hurry im timed
Mathematics
1 answer:
aleksley [76]2 years ago
7 0
The Answer: is B) 3.5

Explanation:
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the answer is -16 x ^3 + 116 x ^2 -96 x -144

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Mr. Jackson ran 7/8 mile on Monday he ran 3/8 of a mile on Wednesday and 5/8 mile on Friday on witch day did Mr Jackson run the
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A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 ce
julsineya [31]

Answer:

The proportion of students whose height are lower than Darnell's height is 71.57%

Step-by-step explanation:

The complete question is:

A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 centimeters. Darnel is a middle school student with a height of 161.4cm.

What proportion of proportion of students height are lower than Darnell's height.

Answer:

We first calculate the z-score corresponding to Darnell's height using:

Z=\frac{X-\mu}{\sigma}

We substitute x=161.4 , \mu=150, and \sigma=20 to get:

Z=\frac{161.4-150}{20} \\Z=0.57

From the normal distribution table, we read 0.5 under 7.

The corresponding area is 0.7157

Therefore the proportion of students whose height are lower than Darnell's height is 71.57%

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Answer:

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Step-by-step explanation:

Hope this helps

4 0
3 years ago
180 students in a tenth grade high school class take a survey about which video game consoles they own.
Fantom [35]

Answer:

P(A) = 44.44%

P(B) = 50%

P(B|A) = 37.5%

P(B|A) different from P(B).

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Step-by-step explanation:

If we have a total of 180 students, and 80 of them have a Playstation, we have that P(A) = 80/180 = 0.4444 = 44.44%

If we have 90 students that have a Xbox, we have that P(B) = 90/180 = 0.5 = 50%

If we have 30 students that have both consoles, we have that P(A and B) = 30/180 = 0.1667 = 16.67%

To find P(B|A), we will find for a student that has an Xbox inside the group of students that has a Playstation, that is, we have 30 students in a total of 80 students, so P(B|A) = 30/80 = 0.375 = 37.5%

P(B|A) is different from P(B), the first is 37.5% and the second is 50%, so events A and B are independent events.

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