If you would like to know what is the area of the paper in square centimeters, you can calculate this using the following steps:
1 inch equals to 2.54 centimeters.
11 inches = 11 * 2.54 = <span>27.94 centimeters long
8.5 inches = 8.5 * 2.54 = </span><span>21.59 centimeters wide
11 inches long * 8.5 inches wide = 27.94 centimeters long * 21.59 centimeters wide = </span>27.94 * 21.59 = 603.22 square centimeters
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The correct result would be </span>603.22 square centimeters.<span>
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3(4x + 6) + 7x
12x + 18 + 7x
19x + 18 <==
Answer:
Lines 3 and 4
Step-by-step explanation:
ignore this rjrjrjrjrrnrnnrnrrnnr
Answer:
25/12 - pounds more vegetables
Step-by-step explanation:
first we need to put these variables into like terms
36/12 - 3
8/12 - 2/3
3/12 - 1/4
add the last two up and subtract from the first and you get how much you need left over
<span>The maxima of a differential equation can be obtained by
getting the 1st derivate dx/dy and equating it to 0.</span>
<span>Given the equation h = - 2 t^2 + 12 t , taking the 1st derivative
result in:</span>
dh = - 4 t dt + 12 dt
<span>dh / dt = 0 = - 4 t + 12 calculating
for t:</span>
t = -12 / - 4
t = 3
s
Therefore the maximum height obtained is calculated by
plugging in the value of t in the given equation.
h = -2 (3)^2 + 12 (3)
h =
18 m
This problem can also be solved graphically by plotting t
(x-axis) against h (y-axis). Then assigning values to t and calculate for h and
plot it in the graph to see the point in which the peak is obtained. Therefore
the answer to this is:
<span>The ball reaches a maximum height of 18
meters. The maximum of h(t) can be found both graphically or algebraically, and
lies at (3,18). The x-coordinate, 3, is the time in seconds it takes the ball
to reach maximum height, and the y-coordinate, 18, is the max height in meters.</span>
