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3 years ago

62 in x 48 in 144 in Set Up Proportion height=

Mathematics

1 answer:

JulijaS [17]3 years ago

5 0

Answer:

A geometric diagram of the two shadows and the height of the two people are shown below.

Step-by-step explanation:

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Which is a property of an angle?

Margaret [11]

Answer:

I believe that it is the last answer. have a great day!

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4 years ago

PLEASE HELP!! algebra 2

Debora [2.8K]

Answer:

your answer is D

Step-by-step explanation:

5 0

3 years ago

2. Suppose 27 blackberry plants started growing in a yard. Absent constraint, the blackberry plants will spread by 80% a month.

Marta_Voda [28]

Explanation

The question indicates we should use a logistic model to estimate the number of plants after 5 months.

This can be done using the formula below;

$\begin{gathered} P(t)=\frac{K}{1+Ae^{-kt}};A=\frac{K-P_{0_{}}}{P_0}_{} \\ \text{From the question} \\ P_0=\text{ Initial Plants=27} \\ K=\text{Carrying capacity =140} \end{gathered}$

Workings

Step 1: We would need to get the value of A using the carrying capacity and initial plants that started growing in the yard.

This gives;

$\begin{gathered} A=\frac{140-27}{27} \\ A=\frac{113}{27} \end{gathered}$

Step 2: Substitute the value of A into the formula.

$P(t)=\frac{140}{1+\frac{113}{27}e^{-kt}}$

Step 3: Find the value of the constant k

Kindly recall that we are told that the plants increase by 80% after each month. Therefore, after one month we would have;

$\begin{gathered} P(1)=27+(\frac{80}{100}\times27) \\ P(1)=\frac{243}{5} \end{gathered}$

We can then have that after t= 1month

$\begin{gathered} \frac{140}{1+\frac{113}{27}e^{-k\times1}}=\frac{243}{5} \\ Flip\text{ the equation} \\ \frac{1+\frac{113}{27}e^{-k}}{140}=\frac{5}{243} \\ 243(1+\frac{113}{27}e^{-k})=700 \\ 243+1017e^{-k}=700 \\ 1017e^{-k}=700-243 \\ 1017e^{-k}=457 \\ e^{-k}=\frac{457}{1017} \\ -k=\ln (\frac{457}{1017}) \end{gathered}$

Step 4: Substitute -k back into the initial formula.

$\begin{gathered} P(t)=\frac{140}{1+\frac{113}{27}e^{\ln (\frac{457}{1017})t}} \\ =\frac{140}{1+\frac{113}{27}(e^{\ln (\frac{457}{1017})})^t} \\ P(t)=\frac{140}{1+\frac{113}{27}(\frac{457}{1017}^{})^t} \\ \end{gathered}$

The above model is can be used to find the population at any time in the future.

Therefore after 5 months, we can estimate the model to be;

$\begin{gathered} P(5)=\frac{140}{1+\frac{113}{27}(\frac{457}{1017}^{})^5} \\ P(5)=\frac{140}{1.07668} \\ P(5)=130.029\approx130 \end{gathered}$

Answer: The estimated number of plants after 5 months is 130 plants.

8 0

1 year ago

Applying the Third Corollary to the Inscribed Angles Theorem A circle is shown. Points A, B, C, and D are on the circle. Lines c

Marat540 [252]

Answer:

∠B = 110°
∠D = 70°

Step-by-step explanation:

Opposite angles in an inscribed quadrilateral are supplementary, so ...

∠B +∠D = 180°

(3x -4) +(2x -6) = 180

5x = 190 . . . . . . . . . . . add 10, collect terms

x = 38 . . . . . . . . . . . . . divide by 5

∠D = 2(38) -6 = 70

∠B = 180 -70 = 110

The measures of angles B and D are 110° and 70°, respectively.

8 0

4 years ago

David rowed a boat upstream for three miles and then returned to point he started from. The entire journey took four hours. The

CaHeK987 [17]

To solve for the time it takes to travel a certain distance at a certain speed, use the formula,
time = distance / speed

Given that the entire journey takes four hours, add up the time it takes David to row upstream with that of him travelling downstream. This is mathematically represented as,

total time = time upstream + time downstream

4 = 3/(x - 1) + 3/(x +1)

Solving for x in the equation gives 2. Thus, David's speed in still water is 2 miles per hour.

7 0

4 years ago

62 in x 48 in 144 in Set Up Proportion height=​

62 in x 48 in 144 in Set Up Proportion height=