I can't understand. Be more specific and I could maybe help. :P
Answer: ∆V for r = 10.1 to 10ft
∆V = 40πft^3 = 125.7ft^3
Approximate the change in the volume of a sphere When r changes from 10 ft to 10.1 ft, ΔV=_________
[v(r)=4/3Ï€r^3].
Step-by-step explanation:
Volume of a sphere is given by;
V = 4/3πr^3
Where r is the radius.
Change in Volume with respect to change in radius of a sphere is given by;
dV/dr = 4πr^2
V'(r) = 4πr^2
V'(10) = 400π
V'(10.1) - V'(10) ~= 0.1(400π) = 40π
Therefore change in Volume from r = 10 to 10.1 is
= 40πft^3
Of by direct substitution
∆V = 4/3π(R^3 - r^3)
Where R = 10.1ft and r = 10ft
∆V = 4/3π(10.1^3 - 10^3)
∆V = 40.4π ~= 40πft^3
And for R = 30ft to r = 10.1ft
∆V = 4/3π(30^3 - 10.1^3)
∆V = 34626.3πft^3
You mean y = b^x.
By plugging different values of x, we find different y-values forming points in the form (x, y).
After 2 or 3 points, we can clearly see that the graph of y = b^x passes through the point (0, 1) and extends forever in the upward direction through quadrant 1.
Answer: 5,000cm³
Well, 1 mL (milliliter) is equivalent to 1 cubic centimeter (cm³). There is 1,000 mL in a liter, so there are 5,000 mL in 5 liters and therefore 5 liters equals 5,000 cm³.
Answer:

Step-by-step explanation:
5.64 : 2.48
2.82 : 1.24
1.41 : 0.62
