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3 years ago

Solve for x: 9.2x -1= 2.3x

Mathematics

2 answers:

Lorico [155]3 years ago

8 0

Answer:

x= 10/69

Step-by-step explanation:

Rina8888 [55]3 years ago

7 0

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Here's the solution :

$9.2x - 1 = 2.3x$

$9.2x - 2.3x = 1$

$6.9x = 1$

$x = \dfrac{1}{6.9}$

$x = \dfrac{10}{69}$

value of x = 10/69 or 0.144 upto three decimal places.

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The average number of passes in a football game is right skewed with mean 75 and variance 961. If we sample 100 random games, wh

suter [353]

Answer:

0.0066

Step-by-step explanation:

Given that:

Mean $\mu$ = 75

Variance $\sigma^2 =961$

The standard deviation $\sigma = \sqrt{961} = 31$

The sample size n = 100

$\mu = \mu_{\overline x} = 75$

$\sigma _{\overline x} = \dfrac{\sigma }{\sqrt{n}}$

$\sigma _{\overline x} = \dfrac{31 }{\sqrt{100}}$

$\sigma _{\overline x} = \dfrac{31 }{10}}$

$\sigma _{\overline x} = 3.1$

$P(\overline x > 83.7) = 1 - P( \overline x < 83.7)$

$P(\overline x > 83.7) = 1 -P\bigg ( \dfrac{\overline x - \mu_{\overline x} }{\sigma _{\overline x}} < \dfrac{83.7 - 76}{3.1} \bigg)$

$P(\overline x > 83.7) = 1 -P\bigg ( Z< \dfrac{7.7}{3.1} \bigg)$

$P(\overline x > 83.7) = 1 -P ( Z< 2.48)$

Using the Z table;

P(x > 83.7) = 1 - 0.9934

P(x > 83.7) = 0.0066

Thus, probability = 0.0066

8 0

3 years ago

George bought 30 packs of football cards There were14 cards in each pack How many cards did george buy

mars1129 [50]

Answer:

420

Step-by-step explanation:

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3 years ago

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rewona [7]

Answer: rectangle does not have all equal sides

Step-by-step explanation:

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3 years ago

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Sedaia [141]

Check the picture below.

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3 years ago

13 and 15<br><br>solve each problem by graphing and slope intercept

mylen [45]

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Step-by-step explanation: The calculations are as follows:

(13) The given equations are

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In the attached figure (a), these two lines are drawn. We can see that The lines intersect at the point P(8, -9). So, the solution to the pair of equations is (8, -9).

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Thus, the correct option is (B).

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3 years ago