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Gnom [1K]
3 years ago
13

Is it possible to have an expression that uses brackets without using any parentheses???Explain.help plz

Mathematics
1 answer:
OverLord2011 [107]3 years ago
6 0
Yes it is possible if it doesn't have parentheses

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Kaylin buys a greeting card for $3.79. She then buys 4 postcards that all cost the same amount. The total cost is $5.11. How muc
Maksim231197 [3]

Answer:

$0.33

Step-by-step explanation:

5.11-3.79=1.32 1.32/4

Hope this helps :)

6 0
3 years ago
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Binaya spent 10 of his pocket money. He has Rs 120 left now. Find:
kozerog [31]

Answer:

$10 and $130

Step-by-step explanation:

If he spent 10 of his pocket money, then he spent 10

Because he spent 10, that means that he had 120 + 10 = 130 at the start

6 0
3 years ago
What are some ways u can break 7 times 9 using distributive property
Arte-miy333 [17]
7×4=28+32=60+3 this is a bit long
3 0
3 years ago
Write regular expressions for the following languages:a. The set of strings over alphabet {a, b, c} with at least one a and at l
dezoksy [38]

Answer and Step-by-step explanation:

a. The strings  {a, b, c} with at least one a and at least one b.

Solution: ∑ = {a, b, c}

where

(a +b +c)(a (a +b +c)*b + b (a +b +c) a (a +b +c)*

b. The set of 0’s and 1’s string whose tenth symbol from the right end is 1.

Sol: (0+1)*1(0+1)9

c. The set of  0’s and 1’s string with at most one pair of consecutive 1’s.

sol: (0+10)(11+∑)(0+10)

8 0
3 years ago
Explain why the graphs of reciprocals of linear functions (except horizontal ones) always have vertical asymptotes,
Naily [24]

Answer:

The reason is because linear functions always have real solutions while some quadratic functions have only imaginary solutions

Step-by-step explanation:

An asymptote of a curve (function) is the line to which the curve is converging or to which the curve to line distance decreases progressively towards zero as the x and y coordinates of points on the line approaches infinity such that the line and its asymptote do not meet.

The reciprocals of linear function f(x) are the number 1 divided by function that is 1/f(x) such that there always exist a value of x for which the function f(x) which is the denominator of the reciprocal equals zero (f(x) = 0) and the value of the reciprocal of the function at that point (y' = 1/(f(x)=0) = 1/0 = ∞) is infinity.

Therefore, because a linear function always has a real solution there always exist a value of x for which the reciprocal of a linear function  approaches infinity that is have a vertical asymptote.

However a quadratic function does not always have a real solution as from the general formula of solving quadratic equations, which are put in the form, a·x² + b·x + c = 0 is  \dfrac{-b \pm \sqrt{b^{2} - 4\cdot a\cdot c}}{2\cdot a}, and when 4·a·c > b² we have;

b² - 4·a·c < 0 = -ve value hence;

√(-ve value) = Imaginary number

Hence the reciprocal of the quadratic function f(x) = a·x² + b·x + c = 0, where 4·a·c > b² does not have a real solution when the function is equal to zero hence the reciprocal of the quadratic function which is 1/(a·x² + b·x + c = 0) has imaginary values, and therefore does not have vertical asymptotes.

6 0
3 years ago
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