Answer:
$0.33
Step-by-step explanation:
5.11-3.79=1.32 1.32/4
Hope this helps :)
Answer:
$10 and $130
Step-by-step explanation:
If he spent 10 of his pocket money, then he spent 10
Because he spent 10, that means that he had 120 + 10 = 130 at the start
7×4=28+32=60+3 this is a bit long
Answer and Step-by-step explanation:
a. The strings {a, b, c} with at least one a and at least one b.
Solution: ∑ = {a, b, c}
where
(a +b +c)(a (a +b +c)*b + b (a +b +c) a (a +b +c)*
b. The set of 0’s and 1’s string whose tenth symbol from the right end is 1.
Sol: (0+1)*1(0+1)9
c. The set of 0’s and 1’s string with at most one pair of consecutive 1’s.
sol: (0+10)(11+∑)(0+10)
Answer:
The reason is because linear functions always have real solutions while some quadratic functions have only imaginary solutions
Step-by-step explanation:
An asymptote of a curve (function) is the line to which the curve is converging or to which the curve to line distance decreases progressively towards zero as the x and y coordinates of points on the line approaches infinity such that the line and its asymptote do not meet.
The reciprocals of linear function f(x) are the number 1 divided by function that is 1/f(x) such that there always exist a value of x for which the function f(x) which is the denominator of the reciprocal equals zero (f(x) = 0) and the value of the reciprocal of the function at that point (y' = 1/(f(x)=0) = 1/0 = ∞) is infinity.
Therefore, because a linear function always has a real solution there always exist a value of x for which the reciprocal of a linear function approaches infinity that is have a vertical asymptote.
However a quadratic function does not always have a real solution as from the general formula of solving quadratic equations, which are put in the form, a·x² + b·x + c = 0 is
, and when 4·a·c > b² we have;
b² - 4·a·c < 0 = -ve value hence;
√(-ve value) = Imaginary number
Hence the reciprocal of the quadratic function f(x) = a·x² + b·x + c = 0, where 4·a·c > b² does not have a real solution when the function is equal to zero hence the reciprocal of the quadratic function which is 1/(a·x² + b·x + c = 0) has imaginary values, and therefore does not have vertical asymptotes.