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Kruka [31]
3 years ago
12

Got behind please help me it’s due tomorrow

Mathematics
1 answer:
Svetlanka [38]3 years ago
7 0
Bye this is like 6 or 7 grade math ask your teacher and listen
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Circles M and K are congruent, QR is congruent to LN and OP is congruent to VW. Find x and y.
nexus9112 [7]

Given, arc QR is congruent to arc LN and arc OP is congruent to arc VW.

And the expressions for each arc in the diagram also given as:

Arc QR = 2x - y, arc LN = 11 , arc OP= 10 and arc VW=5x+y.

Hence, we will get the system of equations as following:

Arc QR = Arc LN

2x - y = 11 ...(1)

Arc OP = Arc VW

5x + y = 10 ...(2)

Next step is to add the two equation to eliminate y so that we can solve the equations for x. Therefore,

2x+5x = 11 + 10

7x = 21

\frac{7x}{7} =\frac{21}{7} Divide each sides by 7.

So, x= 3

Now plug in x=3 in equation (2) to get the value of y.

5(3) + y = 10

15 + y =10

15 + y - 15 = 10 - 15 Subtracting 15 from each sides.

y = -5

So, x=3 and y =-5

3 0
3 years ago
Read 2 more answers
. A conductor with a diameter of 100 mils has an area of
Zielflug [23.3K]
In order to answer the question, you need to know the area of a circle.
Area = pi * r^2
Area = 3.14 * (100/2) ^ 2
Area = 3.14 * 50^2
Area = 7850 mils^2 = 0.00785 in^2
7 0
3 years ago
Y/x^2 + y/x^3<br><br>perform the operation and express your answer as a single fraction​
umka2103 [35]

Answer:

\frac{y}{x^2}+\frac{y}{x^3}=\frac{yx+y}{x^3}

Step-by-step explanation:

Given the expression

\frac{y}{x^2}+\frac{y}{x^3}

Let us perform the operation and express your answer as a single fraction​

\frac{y}{x^2}+\frac{y}{x^3}=\frac{x^3y+x^2y}{x^5}

            =\:\frac{x^2\left(xy+y\right)}{x^5}

            =\frac{\left(xy+y\right)}{x^3}

Therefore, we conclude that:

\frac{y}{x^2}+\frac{y}{x^3}=\frac{yx+y}{x^3}

3 0
3 years ago
An airplane pilot can see the top of a traffic control tower at a 20 degree angle of depression. the airplane is 5,000 feet away
daser333 [38]

The given question describes a right triangle with with one of the angles as 20 degrees and the side adjacent to the angle 20 degrees is of length 5,000 feet. We are looking for the length of the side opposite the angle 20 degrees.

Let the required length be x, then

\tan{20^o}=\cfrac{opp}{hyp}=\cfrac{x}{5,000}\\ \\ \Rightarrow x=5,000\tan{20^o}=1,819.85

Therefore, the height of the airplane above the tower is 1,819.85 feet.

8 0
4 years ago
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Which equation represents the line that passes through the points (1,3) and (-2,5)
Paha777 [63]

Answer:

y= -2/3x+11/3

Step-by-step explanation:

5 0
3 years ago
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