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navik [9.2K]
3 years ago
13

Help please!!! ———————-

Mathematics
2 answers:
Marat540 [252]3 years ago
5 0
B is the answer okay
nadezda [96]3 years ago
4 0
The correct answer is B :)
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Help on #26 please. State the domain and range
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3 years ago
A geometric sequence has first term 1/9 and common ratio 3. Which is the first term of the sequence which exceeds 1000?
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a_{n}= \frac{1}{9}  (3)^{n-1}
(We know this from a=1/9 and r=3)
Simplifying this, we get:
\frac{1}{9} (3)^{-1} (3)^n

Since we're finding the first term that exceeds 1000, let's set it equal to 1000.

\frac{1}{27}(3)^n=1000
Multiplying both sides by 27
3^n=27000

log_{3}27000=n

n≈9.2

We have to round n up, since if n=9, the value would be <1000.
Therefore n=10. Substituting n=10,
\frac{1}{27}3^{10}
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3 0
3 years ago
Please help! Thank you if you do!
vekshin1

Answer:

8/50

5/50

10/50

38/50

45/50

Step-by-step explanation:

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Two elves can make 5 toys in 10 minutes<br> How many toys can four elves make in 30 minutes?
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