This question is Incomplete
Complete Question
Researchers recorded the speed of ants on trails in their natural environments. The ants studied, Leptogenys processionalis, all have the same body size in their adult phase, which made it easy to measure speeds in units of body lengths per second (bl/s). The researchers found that, when traffic is light and not congested, ant speeds vary roughly Normally, with mean 6.20 bl/s and standard deviation 1.58 bl/s. (a) What is the probability that an ant's speed in light traffic is faster than 5 bl/s? You may find Table B useful. (Enter your answer rounded to four decimal places.)
Answer:
0.7762
Step-by-step explanation:
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
Population mean = 6.20 bl/s
Standard deviation = 1.58 bl/s.
x = 5 bl/s
z = 5 - 6.20/1.58
z = -0.75949
The probability that an ant's speed in light traffic is faster than 5 bl/s is P( x > 5)
Probability value from Z-Table:
P(x<5) = 0.22378
P(x>5) = 1 - P(x<5)
= 1 - 22378
= 0.77622
Approximately to 4 decimal places = 0.7762
The probability that an ant's speed in light traffic is faster than 5 bl/s is 0.7762
Answer:
2, 3, 5
Step-by-step explanation:
A∩B means "A intersection B" which includes all elements that are shared in BOTH sets. This would be the middle crossover section of a Venn diagram.
Hence, 2 and 3 and 5 are shared in both sets.
Answer:
I would say d.im pretty sure tho
Multiply the dimensions to get 174,720 in^3
Answer:
1. about 11.18
2. about 8.66
Step-by-step explanation:
1. 5^2 + 10^2= 125
square root of 125 equals about 11.18
2. 10^2-5^2=75
square root of 75 equals about 8.66
