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just olya [345]
2 years ago
9

Given a1 = 1/4 and a common ratio of 8,find the 9th term in the sequence.​

Mathematics
1 answer:
sergey [27]2 years ago
8 0
<h2>PLEASE MARK ME AS BRAINLIEST PLEASE</h2><h3>a1=-256</h3><h3 /><h3>r= -1/4</h3><h3 /><h3>Approximated the sum of the first 17 terms to the nearest tenth. Sum= -204.8</h3>
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An arithmetic series has seven terms. the first term is 5 and the last term is 53. find the sum of the series!
Kisachek [45]
The easiest way is to use (& to memorize) the sum formula for a AP:


Sum = 1st term added to the last term & multiplied by half the number of terms
S = (a+l)n/2

S = (5 + 53)(7/2) = 203 
5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%28%20%5Cfrac%7B1%7D%7B2%7D%20%20%7Ba%7D%5E%7B2%7D%20%20%2B%20%20%20%5Cfrac%7B1%7D%7B2%7D%20ab
Zigmanuir [339]

Answer:

\frac{1}{2} (a + 2b)(a - b)

Step-by-step explanation:

Assuming you require the expression to be factored

Given

\frac{1}{2} a² + \frac{1}{2} ab - b² ← factor out \frac{1}{2} from each term

= \frac{1}{2} (a² + ab - 2b²) ← factor the quadratic

Consider the factors of the coefficient of the b² term(- 2) which sum to give the coefficient of the ab- term (+ 1)

The factors are + 2 and - 1, since

2 × - 1 = - 2 and 2 - 1 = + 1, thus

a² + ab - 2b² = (a + 2b)(a - b) and

\frac{1}{2} a² + \frac{1}{2} ab - b² = \frac{1}{2}(a + 2b)(a - b)

5 0
3 years ago
8. which of the following ordered pairs is a solution of the given system of linear equations
V125BC [204]

Answer:

Option D The solution of the system is the point (-3,5)

Step-by-step explanation:

we have

x+y=2 -----> equation A

y=-2x-1 ------> equation B

Solve the system by substitution

Substitute the equation B in equation A and solve for x

x+(-2x-1)=2

-x-1=2

x=-2-1

x=-3

Find the value of y

y=-2x-1

y=-2(-3)-1

y=5

therefore

The solution of the system is the point (-3,5)

3 0
3 years ago
A child bus ticket costs $0.40 and an adult’s ticket costs $0.70. A group of 11 individuals pays $5.90 for their fare.
oee [108]
Here we have a system of equation like this:
A+B=11\\&#10;0.4A+0.7B=5.9
from the first equation we get:
A=11-B
Substitute in the second equation we get:
0.4(11-B)+0.7B=5.9\\4.4-0.4B+0.7B=5.9\\0.3B=1.5\\B= \frac{1.5}{0.3}=5
Substitute i the first equation again we get:
A=11-B=11-5=6
We deduce that:
A > B A is bigger than B.
5 0
3 years ago
What is the decimal equivalent of 3/6%
GREYUIT [131]

Answer:

0.5

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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