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Oliga [24]
3 years ago
8

Which of the following is a polynomial with roots

Mathematics
2 answers:
PtichkaEL [24]3 years ago
5 0
a(x-x_1)(x-x_2)(x-x_3)\\\\x_1=-\sqrt3;\ x_2=\sqrt3;\ x_3=-2;\ a=1\\\\subtitute\\\\(x+\sqrt3)(x-\sqrt3)(x+2)=(x^2-3)(x+2)\\\\=\boxed{x^3+2x^2-3x-6}\to\fbox{B.}
Anuta_ua [19.1K]3 years ago
5 0
<span> the polynomial has the factor (x-n) </span>
<span>So any polynomial with these roots, must have the factors (x+sqrt(3))(x-sqrt(3))(x+2) </span>
<span>Since these are cubic polynomials (highest x term is x^3), these are all the factors, so the polynomial is of the form: </span>
<span>k(x+sqrt(3))(x-sqrt(3))(x+2) </span>
<span>And since the x^3 term is 1, the constant k must be 1. </span>

<span>So, the polynomial must be the one which is equal to: </span>
<span>(x+sqrt(3))(x-sqrt(3))(x+2) </span>
<span>Since the constant term (the last term) is different for each of your 4 options, you just need to evaluate the constant term and see which one matches. </span>
<span>i.e. the answer is whichever polynomial has a constant term equal to </span>
<span>sqrt(3) times (-sqrt(3)) times 2</span>
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JulsSmile [24]

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(3) The coefficients are unit prices: coefficient 0.50 is the price of 1 apple, 0.30 is the price of 1 banana.

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iragen [17]

Answer:

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3 years ago
Copy the expressions which are polynomials. Give reasons why the remaining are
kupik [55]

Answer: a and c are polynomials, b is not.

Step-by-step explanation:

A polynomial p(x) is written as:

p(x) = aₙ*xⁿ + ... + a₂*x² + a₁*x¹ + a₀*x⁰

where x is the variable, and the numbers aₙ, aₙ₋₁, ..., a₁, a₀ are the coefficients of the polynomial, such that aₙ is the leading coefficient, and the value of n (always a natural number) is the degree of the polynomial.

Notice that the powers need to be always natural numbers.

Now, let's analyze the options:

a) 3*x - 2

We can rewrite this as:

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Then this is a polynomial.

b) p² + 1/p    (in this case the variable is p)

the second term can be written as:

1/p = p⁻¹

Then we have a term with a negative power of p, this means that this is not a polynomial.

c) 3*y² - 2*y/3 + 1

Same as in the first case, we can rewrite this as:

3*y² - (2/3)*y¹ + 1*y⁰

This is a polynomial.

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