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mash [69]
4 years ago
11

Is (5,1) a solution to the equation 2x-y=11? Explain

Mathematics
2 answers:
grigory [225]4 years ago
7 0
This is simple. Coordinate form is (x,y) so you would just plug in your values. 

2(5)-(1)=11

10-1 does not equal 11, so no it is not a solution.
nika2105 [10]4 years ago
6 0
Substitute the x for 5 and the y for 1.

(2)(5) - (1) = 11
10 - 1 = 9
9 does not equal 11
So, (5,1) is not a solution.
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Igoryamba

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3. Simplify is necessary.

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6 0
4 years ago
Given that (-6,2) is on the graph of f(x) find the corresponding point for the function f(1/4x).
Dafna1 [17]
Answer: (-24,2)

=======================================

Work Shown:

The y coordinate stays the same. Only the x coordinate will change.

(1/4)*x = -6
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x = -24 is the new x coordinate
Plugging x = -24 into f((1/4)x) leads to f(-6) = 2

7 0
4 years ago
What is m ABC?<br> m ABC = 15°<br> m ABC = 45°<br> mABC = 60°<br> m ABC = 75°
Amiraneli [1.4K]

Answer:

C) 60

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
(3a^3-5b^3)+blank a^3+blank b^3=(a^3+b^3)
lions [1.4K]

Answer:

(3a³-5b³)+ (-2)a³ +6b³=(a³+b³)

Step-by-step explanation:

First,  lets remove the brackets.  There is no "-" before the brackets, so we can just remove them at all.

3a³-5b³+ ...a³ +...b³=a³+b³

Now we can joint similar monoms (with variable a)  ( and with variable b) in the left side of equation

3a³+...a³ -5b³ +...b³=a³+b³

Now we can notice that 3a³+...a³=a³    (1)  and

-5b³ +...b³=b³    (2)

Lets find deduct 3a³ from both sides of (1)

...a³= a³-3a³

...a³= -2a³  So instead ... we have to type -2 (-2 is negative sowe type -2 in brackets).

Similarly   lets add 5b³ to both sides of (2)

-5b³ +...b³=b³

-5b³ +5b³ +...b³=b³+5b³

...b³=6b³ So instead ... we have to type 6.

6 0
3 years ago
2/5 (3r+4) =10 solve for r
MrRissso [65]

Answer:

x=7

Step-by-step explanation:

✯Hii✯

↪  expand the brackets

↪  then solve normally

↪  x will be 7

❤Kathy❤

8 0
4 years ago
Read 2 more answers
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