In fraction that would be 3/4 because 15/20 simplified would be three quarters.
If thats not the answer, message me back and I will go out of my way to figure out the correct one. Thats my policy :)
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Answer:
D- add the fractions together on the right side of the equation
Step-by-step explanation:
In the previous step, the fractions are written with a common denominator. In the last step, the two fractions are combined (added together).
The best description of those provided is ...
D- add the fractions together on the right side of the equation
Answer:
a) The perimeter of a rectangle is written as:
P = 2*L + 2*W
where L is the length amd W is the width (broad in this case).
here we have:
L = 8cm and W = b
then the perimeter is:
P = 2*8cm + 2*b
And we know that:
18cm ≤ P ≤ 50cm
where ≤ is used because there is written "not more" and "not less", so the equalities are allowed
now we can replace P by the above equation:
18cm ≤ 16cm + 2*b ≤ 50cm
now we can subtract 16cm in each side and get:
18cm - 16cm ≤ 2*b ≤ 50cm - 16cm
2cm ≤ 2*b ≤ 34cm
Now we can divide each side by 2.
1cm ≤ b ≤ 34cm/2 = 17cm
1cm ≤ b ≤ 17cm.
b) Here we have missing information, so this can not be answered.
(only knowing that one side length is x, and another side length is x + 3cm, we can know that x > 0cm, so the minimum value of x is really close to 0cm)
Answer:
5 is a great place to be your
Step-by-step explanation:
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Answer:
x = 13, y = 26
The length of the sides of Δ QRS are QR = 104, <u>QS = 468</u>, RS = 76
Step-by-step explanation:
In ΔRQS
∵ M is the mid-point of side RQ
→ That means M divide RQ into 2 equal parts RM and MQ
∴ RM = MQ
∵ RM = 4x
∵ MQ = 52
→ Equate them
∴ 4x = 52
→ Divide both sides by 4 to get x
∴ x = 13
∵ P is the mid-point of side QS
→ That means P divide QS into 2 equal parts QP and PS
∴ QP = PS
∵ QP = 9y
∵ PS = 234
→ Equate them
∴ 9y = 234
→ Divide both sides by 9 to get y
∴ y = 26
→ Find the length of each side
∵ RQ = 52 + 52
∴ RQ = 104
∵ QS = 234 + 234
∴ QS = 468
∵ RS = 38 + 38
∴ RS = 76
∴ The length of the sides of Δ QRS are QR = 104, QS = 468, RS = 76
Note: PS = 234 is wrong because it made the length of the sides QS = 468, which could not be because the sum of any 2 sides of a triangle must be greater than the 3rd side. So check it.