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2 years ago

Which of the ratios below is equivalent to 2:3? Select all that apply.

Mathematics

1 answer:

nalin [4]2 years ago

5 0

Answer:

Your answers are B, C, and E.

Step-by-step explanation:

They are all equivalent to 2:3.

You might be interested in

A student says that 2 1/4 + 1 2/4 =5. Why is that answer wrong?

saw5 [17]

2 1/4 + 1 2/4 ≠ 5

Why?

2 1/4 + 1 2/4
=3 3/4

The answer is wrong because the student added wrong. The real answer is 3 3/4.

8 0

3 years ago

Subtract. -21 - (-13)

Burka [1]

Answer:

-8

Step-by-step explanation:

-21-(-13)

=-21+13

=-8 is the answer......

3 0

2 years ago

Read 2 more answers

What is the measure of Angle J K L?

ivanzaharov [21]

Answer:

97 degrees

Step-by-step explanation:

180 degrees minus 83 degrees is 97 degrees

3 0

2 years ago

Read 2 more answers

Use the Fundamental Theorem of Calculus to find the "area under curve" of

lozanna [386]

Answer:

$\displaystyle A = 300$

General Formulas and Concepts:

Calculus

Integrals

Definite Integrals
Area under the curve
Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Area of a Region Formula: $\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

f(x) = 6x + 19

Interval [12, 15]

Step 2: Find Area

Substitute in variables [Area of a Region Formula]: $\displaystyle A = \int\limits^{15}_{12} {(6x + 19)} \, dx$
[Integral] Rewrite [Integration Property - Addition/Subtraction]: $\displaystyle A = \int\limits^{15}_{12} {6x} \, dx + \int\limits^{15}_{12} {19} \, dx$
[Integrals] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle A = 6\int\limits^{15}_{12} {x} \, dx + 19\int\limits^{15}_{12} {} \, dx$
[Integrals] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle A = 6(\frac{x^2}{2}) \bigg| \limits^{15}_{12} + 19(x) \bigg| \limits^{15}_{12}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle A = 6(\frac{81}{2}) + 19(3)$
Simplify: $\displaystyle A = 300$