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ss7ja [257]
3 years ago
6

How many different 3-letter codes can be created from the first 8 letters of the alphabet? No letters can repeat.

Mathematics
2 answers:
poizon [28]3 years ago
8 0

Answer:

There are 336 possible codes Hopefully this helps!

timofeeve [1]3 years ago
6 0

There is 336 different codes.

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PLZ HELP ME <br> I appreciate any help, especially if you can show me how you got the answer
Arte-miy333 [17]

Answer:

C

Step-by-step explanation:

Since this is an indererminate form, use L'Hopital

d(sint)/dt = cos(t)

d[ln(2e^t) - 1] = (2e^t)/[2e^t - 1]

As t --> 0,

cos(0) = 1

(2e^t)/[2e^t - 1] = 2

1/2 is the limit

5 0
3 years ago
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LiRa [457]
Um idk sorry lol that’s way to hard for me
5 0
3 years ago
I need to know how to solve this
dedylja [7]

Answer:

C

Step-by-step explanation:

I think you have to call a = 14/32 and b = 7/4

3a = 3 * 14/32 = 42/32

b = 1 3/4 = (4 + 3)/4 = 7/4

42/32 // 7/4                        Invert and multiply

42/32 * 4/7                         Cancel 4 into 32 and 7 into 42

6/8 = 3/4

I make the answer C

3 0
3 years ago
Read 2 more answers
The pizza parlor is running a special on 3-toppings pizzas. The topping choices include pepperoni, sausage, bacon mushrooms, oni
choli [55]

Answer:

Well there are 6 toppings. For one person to select sausage, it is  \frac{1}{6} . For two people, multiply them together and the probability is  \frac{1}{36}

4 0
3 years ago
899 round to the nearest ten
algol [13]
900 because 9 is greater than 5 so it rounds to my answer.
6 0
3 years ago
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