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icang [17]
4 years ago
10

uppose you send about 12 text messages a day, and your older sister sends more text messages than you do. Together, you send a t

otal of about 26 messages per day. About how many text messages does she send a day? Write an equation and solve for the unknown value
Mathematics
1 answer:
Kamila [148]4 years ago
5 0
In order to get your answer, take the number of text messages you send each day (12) and subtract it from the number you and your sister send (26). When you get the answer from subtracting both of these numbers, take the answer from your subtraction and add it to the number of text messages that you send a day (12).
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jok3333 [9.3K]

Answer:

\large \boxed{\sf \ \ \ \dfrac{\sqrt{4025}-5}{2}=29.22144... \ \ \ }

Step-by-step explanation:

Hello

<u>Let's note the original speed of the car v</u>

it means that in 1 hour he is going v miles

so to go 200 miles it takes ( in hour)

\dfrac{200}{v}

If the speed of the car is v+5 than to go 200 miles it takes (in hour)

\dfrac{200}{v+5}

and this time is one hour less so we can write

\boxed{\sf \ \ \dfrac{200}{v+5}=\dfrac{200}{v}-1 \ \ }

We can multiply by v(v+5) both parts of the equation so

200v=200(v+5)-v(v+5)\\\\200v=200v+1000-v^2-5v\\\\v^2+5v-1000=0

\Delta=b^2-4ac=5^2+4*1000=4025\\\\ \text{There are potential solutions }\\\\\ \ \ \ \ x_1=\dfrac{-5-\sqrt{4025}}{2}\\\\\ \ \ \ \ x_2=\dfrac{-5+\sqrt{4025}}{2}

Only one is positive and this is is

x_1=\dfrac{\sqrt{4025}-5}{2}=29.22144...

So the original speed is 29.22144... mph

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

7 0
3 years ago
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Sladkaya [172]

Answer:

600

Step-by-step explanation:

i hope tht helped I had tht question a couple days ago

6 0
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Answer:

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Step-by-step explanation:

Given the question :

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Since Michael has decided to dedicate the entirety of his signing bonus towards paying his debt, then that is a constant and one-off payment.

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Total debt amount = 36,700

Size of debt left after m months :

Total debt - ( signing bonus - fixed amount × m)

Hence signing bonus = 5000

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For x\neq a, we have

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