Susanne is 16 years old.
b = Bob's age
s = Susanne's age
d = Dakota's age
Bob's age is 4 times greater than Susanne's age:
b = 4s
Dakota is three years younger than Susanne:
d = s - 3
The sum of Bob's, Susanne's, and Dakota's ages is 93:
b + s + d = 93
solve these equations:
b = 4s
d = s - 3
b + s + d = 93
and get:
b = 64 years
s = 16 years
(remember that s = Susanne)
d = 13 years
It’s like -5 or something maybe
Answer:
See below ~
Step-by-step explanation:
<u>Sin A</u> : opposing side of ∠A / hypotenuse
<u>Sin C</u> : opposing side of ∠C / hypotenuse
<u></u>
<u>Cos A</u> : adjacent side of ∠A / hypotenuse
<u></u>
<u>Cos C</u> : adjacent side of ∠C / hypotenuse
Answer:
it is very high because
Step-by-step explanation:
5-2+3 so maybe it a subtraction problem hope this works
