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EleoNora [17]
3 years ago
6

Given the polynomial function below find F(-4) f(x)=2x^ 2 -x + 9

Mathematics
1 answer:
fenix001 [56]3 years ago
5 0

Answer:

45

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=f%28x%29%3D-4x%5E%7B2%7D%2B5x" id="TexFormula1" title="f(x)=-4x^{2}+5x" alt="f(x)=-4x^{2}+5x"
JulijaS [17]

Answer:

Domain= (-inf,inf)/(-∞,∞)

Range= (-inf,25/16]

x-intercepts= (0,0), (5/4,0)

y-intercepts=(0,0)

vertex= maximum (5/8,25/16)

8 0
3 years ago
Find m∠ABD and m∠CBD given m∠ABC = 111∘.
sineoko [7]

Answer:

m∠ABD = 88º

m∠CBD = 23º

Step-by-step explanation:

(-10x + 58) + (6x + 41) = 111

Combine like terms

-4x + 99 = 111

Subtract 99 from both sides

-4x = 12

Divide both sides by -4

x = -3

------------------------

m∠ABD = -10x + 58

m∠ABD = -10(-3) + 58

m∠ABD =  = 30 + 58

m∠ABD = 88º

m∠CBD = 6x + 41

m∠CBD = 6(-3) + 41

m∠CBD = -18 + 41

m∠CBD = 23º

7 0
3 years ago
Read 2 more answers
Find the absolute maximum and absolute minimum values of f on the given interval. f(x) = 16 + 2x − x^2, [0, 5]
RSB [31]

Answer:

<h2>absolute maximum = 16</h2><h2>absolute minimum = 1</h2>

Step-by-step explanation:

To get the absolute maximum and minimum values of the function f(x) = 16 + 2x − x² n the given interval [0,5], we need to get the values of f(x) at the end points. The end points are 0 and 5.

at x = 0;

f(0) =  16 + 2(0) − 0²

f(0) = 16

at the other end point i.e at x = 5;

f(5) =  16 + 2(5) − 5²

f(5) = 16 + 10-25

f(5)= 26-25

f(5) = 1

The absolute minimum value is 1  and  occurs at x  = 5

The absolute maximum value is 16 and  occurs at x  = 0

5 0
3 years ago
*****NEED ANSWER ASAP*****
Kay [80]

Answer:

-1.2 that is the point hope this helps

Step-by-step explanation:


5 0
3 years ago
The figure below has a volume of 60 cubic units. How many more cubes will it take to fill the figure?
jolli1 [7]

Answer:

40 cubic units

Step-by-step explanation:

4 0
2 years ago
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