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Mandarinka [93]
2 years ago
7

Can some pls help me

Mathematics
1 answer:
Lilit [14]2 years ago
7 0

Answer:

B) -3

Step-by-step explanation:

The sum of the three angles of any triangle is equal to 180 degrees.

180-50-87 = 43.

43 = x+46

x = 43-46

x = -3

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Which of the following is a solution to the inequality 3x-y<5
Ne4ueva [31]

Answer:

not possible

Step-by-step explanation:

they are all greater than 5

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2 years ago
True or False?<br> If false provide an example <br><br> For all integers<br> n, n3 is positive.
Maksim231197 [3]

Answer:

False

Step-by-step explanation:

Explanation is given below.

7 0
3 years ago
The angles with measures x and 4x are complementa angles.which is the value of x
pochemuha

Answer:

\huge\boxed{x=18^o}

Step-by-step explanation:

Two angles are Complementary when they add up to 90°.

Therefore

x+4x=90\qquad|\text{combine like terms}\\\\5x=90\qquad|\text{divide both sides by 5}\\\\\dfrac{5x}{5}=\dfrac{90}{5}\\\\\boxed{x=18}

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3 years ago
Graphing Worksheet
kompoz [17]
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4 0
3 years ago
A population of insects grows exponentially, as shown in the table. Suppose the increase in population continues at the same rat
Ivanshal [37]

We are told that a population of insects grows exponentially and we are given a table of data about insect population growth. We are asked to find population of insects at the end of week 11.        

The initial insect population is 20 and at the end of 1st week population increases to 30.

Let us find growth percentage of insect  population,

\text{Growth percentage}=\frac{\text{Difference}}{Actual} \cdot100

\text{Growth percentage}=\frac{\text{30-20}}{20} \cdot100

\text{Growth percentage}=\frac{\text{10}}{20} \cdot100

\text{Growth percentage}=0.5 \cdot100=50

We can see that insect population is growing at rate of 50% per week.

Now let us write an exponential function for our population.

P(w)=20(1+0.50)^{w}, where P(w) represents population at the end of w weeks.

Let us substitute w=11 in our function to find insect population at the end of 11 weeks.

P(11)=20(1+0.50)^{11}

P(11)=20(1.50)^{11}

P(11)=20\cdot 86.49755859375

P(11)=1729.951171875\approx 1730

Therefore, population of insects at the end of 11th week will be 1730.  



7 0
3 years ago
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