Answer:
please provide full question......
The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
</span>
Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
Answer:
x = 10
Step-by-step explanation:
if there 2 same triangle then they are right triangle
By using Pythagorean theorem for 1 of right triangle, we have
= 
+ 
74 = 49 + 
74 - 49 =
25 =
therefore, x = 
= 
= 10
Answer:
50 mph
Step-by-step explanation:
<u>Speed of Jaguar given:</u>
- 2.5 miles in 3 mins
- Speed in mph = ?
<u>Solution:</u>
- 2.5 miles / 3 mins =
- 2.5 miles / (3/60 h) =
- 2.5*60/3 mph =
- 2.5*20 mph =
- 50 mph
