um what
sory not understand from finland good luck
Answer:
For the 99th percentile, we have X = 206 seconds.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
99th percentile:
Value of X when Z has a pvalue of 0.99. So we use 
For the 99th percentile, we have X = 206 seconds.
Answer:
Actual mean: 223 pages
Predicted mean / estimate: 225 pages
Explanation below
Step-by-step explanation:
Mean = total amount ÷ # of numbers
155 + 214 + 312 + 198 + 200 + 170 + 250 + 260 + 215 + 256
Add
2,230
# of numbers = 10
2,230 ÷ 10 = 223
The exact mean is 223
If I were to predict the mean, I would say that a good estimation would be around 225, because I see that the highest number in the data set is 312, and the lowest is 155. If 312 is rounded down to 300, and 155 is rounded down to 150, the number exactly in the middle of 300 and 150 is 225.
Actual mean: 223 pages
Predicted mean: 225 pages
Hope this helps :)
<span>A dust particle weighs 7.42 × 10-10 kilograms.
Weight of 5 × 106 dust particles = </span>5 × 10^6 x 7.42 x 10^(-10)
= 5 x 7.42 x 10^(6-10)
= 37.1 x 10^(-4)
= 3.71 x 10^(-3) kilograms
Answer:
It is 7 2/11 is less then 7 4/10
Step-by-step explanation:
You do not have to worry about the whole number because they are the same. You have to compare the fractions, so if comparing fractions 10 is less then 11 so 1/10 has a larger space then 1/11. That is how i got the answer. Hope this helps. Am I right?
