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Readme [11.4K]
3 years ago
6

New unit i’m confused

Mathematics
1 answer:
photoshop1234 [79]3 years ago
3 0

Answer:

part a is infinite Part b is number 3

Step-by-step explanation:

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John has 6 boxes of cans. Each box contains 8 cans. What is the total number of cans John has? i dont understand for my sis
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Solve the following system of equations: 2x + 4y − 3z = −7 3x + y + 4z = −12 x + 3y + 4z = 4
lukranit [14]

2x + 4y − 3z = −7 ---> first equation

3x + y + 4z = −12   ---> second equation

x + 3y + 4z = 4   ---> third equation

We try to eliminate z  and make two equations

Multiply first equation by 4 and second equation by 3. then add both equations

8x + 16y -12z = -28

9x + 3y +12z = -36

----------------------------

17x + 19y = -64   ---------------> equation 4

multiply third equation by -1  and add second and third equation

3x + y + 4z = −12  

-x - 3y - 4z = -4    

-------------------------------------

2x -2y = -16        ---------------> equation 5

Multiply equation 4 by 2 and equation by 19

34x + 38y = -128

38x - 38y = -304

------------------------------------

72x  = -432

Divide by 72 on both sides

x = -6

use equation 2x -2y = -16        ---------------> equation 5

2(-6) - 2y = -16

-12 -2y = -16

-2y = -4

So y = 2

Now plug in 2 for y  and -6 for x

Using any one of the three equations

x + 3y + 4z = 4  

-6 + 3(2) +4z = 4

4z = 4 (divide by 4 on both sides)

So z=1

So x= -6, y = 2  and z= 1





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3 years ago
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6 x 6 x 6 x 6 x 6 x 6 x 6 x 6
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Geometry!!!!!!!!!!!!!!!!!!!!!!!!
Stella [2.4K]

<u>Given</u>:

Given that O is the center of the circle.

The radius of the circle is 3 m.

The measure of ∠AOB is 30°

We need to determine the length of the major arc ACB

<u>Measure of major ∠AOB:</u>

The measure of major angle AOB can be determined by subtracting 360° and 30°

Thus, we have;

Major \ \angle AOB=360-30

Major \ \angle AOB=330^{\circ}

Thus, the measure of major angle is 330°

<u>Length of the major arc ACB:</u>

The length of the major arc ACB can be determined using the formula,

<u></u>m \widehat{ACB}=(\frac{\theta}{360})2 \pi r<u></u>

Substituting r = 3 and \theta=330, we get;

m \widehat{ACB}=(\frac{330}{360})2 \pi (3)

m \widehat{ACB}=\frac{1980}{360}\pi

m \widehat{ACB}=5.5 \pi

Thus, the length of the major arc ACB is 5.5π m

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3 years ago
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