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3 years ago

15

Write the standard form of the number shown.

2 answers:

Licemer1 [7]3 years ago

8 0

Answer:230,344,996 is in number form

Step-by-step explanation:

postnew [5]3 years ago

5 0

230,344,996

if this works mark brainliest pls

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Plz helps me I don’t get these I’m hoping for a smart math helper

fenix001 [56]

1) since the probability of garden is 3/20, the total number of cards has to be a multiple of ten. 10 and 20 do not work, but 30 does. number 1 is 30

2) since the odds are 2/5, they're had to be 2/5*30=12

3) since the odds are3/10, there are 3/10*30=9

4)

8 0

3 years ago

Read 2 more answers

Kevin will take 4 math tests this term. All of the tests are worth the same number of points. After taking the first 3 tests, hi

Makovka662 [10]

Answer:

Kevin needs 96 points on his last test to raise his mean test score to 90 points.

Step-by-step explanation:

we know that

The mean score is the total of all scores divided by the total number of tests.

Let

x_1 ----> the score in the first math test

x_2 ----> the score in the second math test

x_3 ----> the score in the third math test

x_4 ----> the score in the fourth math test

we have

After taking the first 3 tests, his mean test score is 88 points

so

$\frac{x_1+x_2+x_3}{3} =88$

$x_1+x_2+x_3=264$ ----> equation A

How many points does he need on his last test to raise his mean test score to 90 points?

so

$\frac{x_1+x_2+x_3+x_4}{4} =90$

$x_1+x_2+x_3+x_4=360$ ----> equation B

substitute equation A in equation B

$264 + x_4 = 360$

solve for x_4

$x_4 = 360-264$

$x_4 = 96$

Therefore

Kevin needs 96 points on his last test to raise his mean test score to 90 points.

4 0

4 years ago

Kari and Kelly are selling spirit ribbons to raise money for the basketball team. The graph shows the relationship between the n

nikdorinn [45]

On day 3, the chart meets up at the same point, so on that day they will have had the same number left.

Step-by-step explanation:

6 0

3 years ago

Two candidates are randomly selected. a. List all the possible outcomes. b. What is the probability that both are qualified? c.

steposvetlana [31]

Question:

Four candidates are to be interviewed for a job. Two of them, numbered 1 and 2, are qualified, and the other two, numbered 3 and 4, are not.

Answer:

a. S = {12,13,14,23,24,34}

b. 1/6

c. ⅔

Step-by-step explanation:

Let S = Sample Space i.e. total possible outcomes

Given that candidates 1 and 2 are qualified and 3 and 4 are not qualified.

If two candidates are randomly selected. The list of all possible outcomes is as follows

S:{12,13,14,23,24,34}

And the number of outcomes is 6

b. What is the probability that both are qualified?

The event that both are qualified is given as {12} or {21}

From the sample space in (a) above, there's only one occurrence of {12} = 1

So, the probability is calculated as 1/6

c. What is the probability that exactly one is qualified?

The event that one one is qualified is given as {13,14,23,24}

Total = 4

Probability = 4/6

Probability = ⅔

5 0

4 years ago

Does anyone know what 0.03 divided by 18 is and could you pls show the work?

Flauer [41]

The answer is 0.0016 or 0.0017

6 0

3 years ago