2a^2b^3(4a^2+3ab^2-ab)=?
<span>
is what I presume you actually meant. </span>
<span>
Pull out the common factors of (4a^2+3ab^2-ab) and you will get </span>
<span>
a(4a+3b^2 -b) </span>
Substitute this back into the original equation and you get
<span>
2a^2b^3[a(4a+3b^2-b)] = </span>
2a^3b^3(4a+3b^2-b) =
<span>2a^3b^3(4a-b+3b^2)
</span>
Answer:
-2
Step-by-step explanation:
When you insert the given points you get
Than you multiply the first one by - 1 and sum it with the second to get rid of n
Hello,
Let y=sin^(-1)(12/13.
==>sin y=12/13
==>cos y=√(1-(12/13)²)=√(25/169)=5/13
Answer 5/13
Answer:
5/4, 1.3, 1 8/25
Step-by-step explanation:
5/4 is equal to 1 1/4, which is 1.25
1.3 is still 1.3
1 8/25 is equal to 1.32, which is sliglightly greater than 1.3
Answer:
the last answer is -1 :))))))
