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Dmitry_Shevchenko [17]
2 years ago
12

Y=2x+3 y=3x+1 solve the system of equations using substitution

Mathematics
2 answers:
marishachu [46]2 years ago
7 0

Answer:

x= 2 and y= 7

Step-by-step explanation:

Substitution method involves getting value of one variable from one equation in terms of other variable and putting this in second equation to eliminate and find value of other variable.

Here we have

y=2x + 3

in first equation and putting this in second equation, we get

2x + 3 = 3x + 1 or

2x - 3x = 1 -3 or

-x = -2

i.e.

x = 2

Putting this Vale of x back in first equation, we get

y = 2 × 2 + 3 = 7

Hence we get x = 2 and y = 7.

Lynna [10]2 years ago
4 0

Answer:

(2, 7 )

Step-by-step explanation:

Given the 2 equations

y = 2x + 3 → (1)

y = 3x + 1 → (2)

Substitute y = 3x + 1 into (1)

3x + 1 = 2x + 3 ( subtract 2x from both sides )

x + 1 = 3 ( subtract 1 from both sides )

x = 2

Substitute x = 2 into either of the 2 equations for corresponding value of y

Substituting x = 2 into (1)

y = 2(2) + 3 = 4 + 3 = 7

Solution is (2, 7 )

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3 years ago
Determine the value of x in the equation x+5x=5x+7
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\text{Hey there!}

\mathsf{Determine\ the\ value\ of\ x\ in\ the\ equation\ x+5x=5x+7.}

\mathsf{SIMPLIFY\ both\ sides\ of\ your\ equation}

\mathsf{x+5x=5x+7}

\mathsf{COMBINE\ your\ like\ terms}

\mathsf{(x+5x)=(5x+7)}

\mathsf{The\ RIGHT\ side\ DOES\  NOT\ have\ any\ like\ terms\ so\ we\ can}\\\mathsf{can\ leave\ alone}

\mathsf{x+5x= 6x}

\mathsf{Your\ new\ equation: 6x=5x+7}

\mathsf{SUBTRACT\ by\ 5x\ on\ your\ sides}

\mathsf{6x-5x}\\\mathsf{=}\\\mathsf{7-5x}

\mathsf{SOLVE\ your\ equation\ above\uparrow}

\mathsf{If\ you\ SOLVED\ correctly\ you\ SHOULD\ have\ the\ VALUE\ of\ x}

\boxed{\boxed{\mathsf{Thus\ your\ answer\ is\ x=7}}}\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\dfrac{\frak{LoveYourselfFirst}}{:)}

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3 years ago
Dy/dx = (cos x) e^(y+sinx) and y = 0 when x = 0. find the original equation
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dy / dx = cosx℮^(y + sinx) 
dy / dx = cosx℮ʸ℮^(sinx) 
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∫ ℮^(-y) dy = ∫ cosx℮^(sinx) dx 
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y = -ln[C - ℮^(sinx)] 

Find the particular solution by solving for the constant: 
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<span>y = -ln[2 - ℮^(sinx)]


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!</span>
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