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3 years ago

Y=2x+3 y=3x+1 solve the system of equations using substitution

Mathematics

2 answers:

marishachu [46]3 years ago

7 0

Answer:

x= 2 and y= 7

Step-by-step explanation:

Substitution method involves getting value of one variable from one equation in terms of other variable and putting this in second equation to eliminate and find value of other variable.

Here we have

y=2x + 3

in first equation and putting this in second equation, we get

2x + 3 = 3x + 1 or

2x - 3x = 1 -3 or

-x = -2

i.e.

x = 2

Putting this Vale of x back in first equation, we get

y = 2 × 2 + 3 = 7

Hence we get x = 2 and y = 7.

Lynna [10]3 years ago

4 0

Answer:

(2, 7 )

Step-by-step explanation:

Given the 2 equations

y = 2x + 3 → (1)

y = 3x + 1 → (2)

Substitute y = 3x + 1 into (1)

3x + 1 = 2x + 3 ( subtract 2x from both sides )

x + 1 = 3 ( subtract 1 from both sides )

x = 2

Substitute x = 2 into either of the 2 equations for corresponding value of y

Substituting x = 2 into (1)

y = 2(2) + 3 = 4 + 3 = 7

Solution is (2, 7 )

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1 year ago

Jose borrowed $800 from his local credit union for 8 months at 6% simple interest. He agreed to pay the loan by making 8 equal m

Nimfa-mama [501]

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3 years ago

What number do i multiply π(pi)^2 by to end up with a number with no decimal

Tomtit [17]

Answer:

Step-by-step explanation:

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2 years ago

Read 2 more answers

Y=6x - 11 -2x - 3y = -7

Ray Of Light [21]

<h2>Therefore x=2 and y= 1</h2>

Step-by-step explanation:

Given equations are

$y = 6x -11$ and $-2x -3y = -7$ .........(2)

⇒ $y - 6x = -11$ .......(1)

Equation (2)× 3 - Equation (1)

$-6x -9y -(y-6x) = -21 -(-11)$

⇔ $-6x -9y-y+6x=-21+11$

⇔-10y = -10

⇔y=1

Putting the value of y in equation (1) we get

$1 = 6x -11$

⇔x =2

Therefore x=2 and y= 1

3 0

3 years ago

John and Tim are looking at the equation the square root of the quantity of 3 times x minus 4 equals square root of x . John say

IgorC [24]

The equation is
3x - 4 = sqrt(x)
where 'sqrt' is shorthand for 'square root'

Let's solve the equation. To do so, we square both sides. Then we get everything to one side
3x - 4 = sqrt(x)
(3x - 4)^2 = (sqrt(x))^2
9x^2 - 24x + 16 = x
9x^2 - 24x + 16-x = x-x
9x^2 - 25x + 16 = 0

Now use the quadratic formula. See the attached image for those steps.

After using the quadratic formula the two possible solutions are x = 1 or x = 16/9

We need to check each possible solution to see if it is extraneous or not.

----------------------------

Checking x = 1

3x - 4 = sqrt(x)
3*1 - 4 = sqrt(1)
3 - 4 = 1
-1 = 1

The final equation is false, so x = 1 is not a true solution

x = 1 is extraneous.

So far, John is correct; however, we need to see the nature of the possible solution x = 16/9

So let's check it
----------------------------

Checking x = 16/9

3x - 4 = sqrt(x)
3*(16/9) - 4 = sqrt(16/9)
48/9 - 4 = 4/3
16/3 - 4 = 4/3
16/3 - 12/3 = 4/3
(16 - 12)/3 = 4/3
4/3 = 4/3

The last equation is true, so x = 16/9 is a proper solution.

This solution is considered non-extraneous. So Tim is also correct
----------------------------

They are both correct because there are two possible solutions. One of which is extraneous (x = 1) and the other is non-extraneous (the fraction x = 16/9)

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3 years ago