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bixtya [17]
3 years ago
5

PLEASE HURRY !!! Mrs. Darbonne has $3.10 in nickels and dimes. She has 10 fewer nickels than she has dimes. How many dimes does

she have? How many nickels does she have?
Mathematics
1 answer:
GrogVix [38]3 years ago
7 0
She has in nickels 50 and she has $2.60 left
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A point estimate of the percentage of defectives in all manufactured bulbs is_____.​
Kobotan [32]

Answer:

inih bagus menurut kamuh inih bagus tidak

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What are the answers to the questions? Picture Below.
velikii [3]
Step 1: Distributive Property
Step 2: Commutative Property
And I think Step 3 & 4 is Associative Property
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Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.
arsen [322]

Answer:

The probability that a randomly chosen person gets an incorrect diagnosis is 2.965% = 0.02965.

Step-by-step explanation:

Given, The test to detect the presence of a liver disorder is 98% accurate for a person who has the disease.

so, probability of incorrect diagnosis = 100-98 = 2% = 0.02.

and 97% accurate for a person who does not have the disease.

so, probability of incorrect diagnosis = 100-97 = 3% = 0.03.

And 3.5% of the people in a given population actually have the disorder.

⇒ the probability that a randomly chosen person gets an incorrect diagnosis is        (3.5% × 0.02) + (96.5% × 0.03) = 2.965% = 0.02965.

5 0
3 years ago
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Identify the probability to the nearest hundredth that a point chosen randomly inside the rectangle is in the square. Only answe
wel

Answer:

0.07

Step-by-step explanation:

we know that

The probability that a point chosen randomly inside the rectangle is in the square is equal to divide the area of the square by the area of rectangle

Let

x-----> the area of square

y----> the area of rectangle

P -----> the probability

P=\frac{x}{y}

<em>Find the area of square (x)</em>

A=5^{2}=25\ in^{2}

<em>Find the area of rectangle (y)</em>

A=25*15=375\ in^{2}

Find the probability P

P=\frac{25}{375}=0.07

7 0
3 years ago
Five times the sum of a number and 27 is greater than or equal to six times the sum of that
AleksAgata [21]

The complete version of question:

<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>

Answer:

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

Step-by-step explanation:

As the description of the statement is:

'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>

<em />

As

  • <em>Five times the sum of a number and 27  </em>is written as: 5(x + 27)
  • <em>greater than or equal </em>is written as:  \geq
  • <em>six times the sum of that number and 26'  </em>is written as: 6(x + 26)

so lets combine the whole statement:

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

solving

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

<em />5x+135\ge \:6x+156<em />

<em />5x+135-135\ge \:6x+156-135<em />

<em />5x\ge \:6x+21<em />

<em />5x-6x\ge \:6x+21-6x<em />

<em />-x\ge \:21<em />

<em />\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}<em />

<em />\left(-x\right)\left(-1\right)\le \:21\left(-1\right)<em />

<em />x\le \:-21<em />

Therefore,

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

6 0
3 years ago
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