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3 years ago

I need hlp with this sorry didn't know I didn't add an attachment the first time.

Mathematics

1 answer:

Eva8 [605]3 years ago

8 0

the answers are

7/10

306/1000

1/100

9/1000

hope this helps!

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During a concert, $3280 was received. A total of 760 people attended. Reserved seats were $6 and general admission seats were $4

Andre45 [30]

Answer:

The number of reserved seat is 120 and number of general seat is 640.

Step-by-step explanation:

Given,

Total number of seats = 760

Total collected Money = $3280

Solution,

Let the total number of reserved seat be x.

And the total number of general seat be y

Hence total number of seats is the sum of total number of reserved seat and the total number of general seats.

So the equation can be written as;

$x+y=760\ \ \ \ equation\ 1$

Again, total money collected is the sum of fees of one reserved seat times total number of reserved seat and fees of one general seat times the total number of general seats.

So the equation can be written as;

$6x+4y=3280\ \ \ \ \ equation\ 2$

Now, multiplying equation 1 by 4 and then subtract it from equation 2.

$4x+4y=3040$

$(6x+4y)-(4x+4y)=3280-3040\\\\2x=240\\\\x=\frac{240}{2}=120$

On substituting the value of x in equation 1, we get;

$x+y=760\\120+y=760\\y=760-120=640$

Thus the number of reserved seat is 120 and number of general seat is 640.

8 0

3 years ago

O Mr. Math S. Fun is looking for his missing pair of

dalvyx [7]

Answer:

1/3

Step-by-step explanation:

add all of the totals including the missing pair

we now have 24

7+1 is 8

24 minus 8 is 16

24 can be split into 2 groups of 8

and we have 2/3 left. which makes our solution 1/3

3 0

2 years ago

Omealio received a grade of 80 on Exam 1. If his grade in Exam 2 was 15% higher, what was his grade in Exam 2? Please help

ExtremeBDS [4]

Answer:

well if the max grade he could get was 100 then you need to find 15% of 100 which is 15, after that add 15 to 80 and you get 95.

his grade for exam 2 was 95

Step-by-step explanation:

15% of 100 = 15

80 + 15 = 95

7 0

3 years ago

Read 2 more answers

The random variable X~(30,2^2) Find p(X<33) Find p(X>26)

Ostrovityanka [42]

Answer:

i) P(X<33) = 0.9232

ii) P(X>26) = 0.001

Step-by-step explanation:

Step(i):-

Given that the mean of the Population = 30

Given that the standard deviation of the Population = 4

Let 'X' be the Normal distribution

Step(ii):-

Given that the random variable X = 33

$Z = \frac{x-mean}{S.D}$

$Z = \frac{33-30}{2} = 1.5$ >0

P(X<33) = P( Z<1.5)

= 1- P(Z>1.5)

= 1 - ( 0.5 - A(1.5))

= 0.5 + 0.4232

P(X<33) = 0.9232

Step(iii) :-

Given that the random variable X = 26

$Z = \frac{x-mean}{S.D}$

$Z = \frac{33-26}{2} = 3.5$ >0

P(X>26) = P( Z>3.5)

= 0.5 - A(3.5)

= 0.5 - 0.4990

= 0.001

P(X>26) = 0.001

5 0

3 years ago

A region c B region d C region a D region b

anyanavicka [17]

Answer:

Region C

Step-by-step explanation:

y ≤ ¼ x + 3 maps the areas C and D including the common boundary line

y ≥ -x + 5 maps the areas B and C including the common boundary line

The common area mapped is C plus its boundaries

3 0

3 years ago