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torisob [31]
3 years ago
6

Convert 6200 seconds into weeks. Round your answer to the nearest hundredth

Mathematics
1 answer:
musickatia [10]3 years ago
6 0

Answer:

0.01 weeks

Step-by-step explanation:

1 min=60sec

1hr=3600sec

1 day = 86400sec

1 week= 604800sec

Therefore answer is 6200/604800= 0.01(approximated)

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Evaluate [(40 + 5) − 32] ÷ 9 ⋅ 2<br><br> 9.3<br> 8.6<br> 8<br> 2
kirza4 [7]

Answer:

its suposed to be written [(40+5)-3^2]÷9·2

so the answer would be C.8

Step-by-step explanation:

first do whats in the brackets but inside the ark looking brackets first

[(40+5)-3^2]÷9·2

will be [45-3^2]÷9·2

and then you do the rest of the brackets but first you square 3 sitch will be come 9

so [45-9]÷9·2

witch will become

36÷9·2

now divide by 9 and get

4·2

witch is going to be

8

therefore the answer is C.8

if brainiest is earned then its greatly appreciated. have a wonderful day

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3 years ago
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The quotient of 100 and 5, increased by 3
Contact [7]

Answer:

23

Step-by-step explanation:

100/5=20

20+3=23

7 0
3 years ago
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$43,000 at 11% for 4 years
love history [14]

Answer:

18920

Step-by-step explanation:

43000*(11/100)*4

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3 years ago
What is the value of x in the equation 4 . 10 X+52 3 +35x+1 5 ?<br><br>:)​
pashok25 [27]

Answer:

x=-3

Step-by-step explanation:

Given:

4\frac{3}{10}-(2\frac{2}{5}x+5\frac{1}{2})=\frac{1}{2}(-3\frac{3}{5}x+1\frac{1}{5})

Distribute to remove parentheses:

4\frac{3}{10}-2\frac{2}{5}x-5\frac{1}{2}=-\frac{18}{10}x+\frac{6}{10}

For simplification and clarity, reduce all mixed numbers to simplified common fractions:

\frac{43}{10}-\frac{12}{5}x-\frac{11}{2}=-\frac{9}{5}x+\frac{3}{5}

Combine like terms:

-\frac{12}{5}x-\frac{6}{5}=-\frac{9}{5}x+\frac{3}{5}

Add 6/5 to both sides, then add 9/5x to both sides:

-\frac{3}{5}x=\frac{9}{5}

Divide both sides by -3/5 to isolate x (recall dividing by a number is equal to multiplying by its reciprocal):

x=\frac{9}{5}\cdot -\frac{5}{3}, \\x=\frac{-9}{3},\\x=\boxed{-3}

3 0
3 years ago
What is the range of this function?
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The range of the function is A
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