Plz answer urgent...A total of 247 students were surveyed about what they liked best for lunch. The results can be shown in a tw
o-way frequency table. Fill in the table below and answer the questions
2 answers:
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Answer:
a)
b) 3,624.25 pounds
Step-by-step explanation:
a)
Since 4300/25 = 172, in average every single person should weight 172 pounds to exceed the design limit.
The probability that one person weights 172 pounds or more is the area under the Normal curve with mean 160 pounds and standard deviation 30 pounds to the right of 172.
<em>In Excel and OpenOffice Calc, this value is found with the formula </em>
<em>=1-NORMDIST(172;160;30;1) </em>
<em> (NORMDIST(172;160;30;1) gives the area to the left of 172, so 1-NORMDIST(172;160;30;1) gives the area to the right of 172) </em>
and equals 0.3446
(see picture 1)
Hence, the probability that all the 25 people exceeds 172 pounds equals
b)
Similarly, we must find a weight w such that if p is the area to the left of w, then
so
w would be the point such that the area under the Normal curve with mean 160 pounds and standard deviation 30 pounds to the right of w equals 0.6918.
<em>In Excel and OpenOffice Calc this is found with </em>
<em>=NORMINV(1-0.6918;160;30) </em>
and equals 144.97 pounds
(See picture 2)
and the design limit that is exceeded by 25 occupants with probability 0.0001 is 25*144.97 = 3,624.25 pounds
