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eduard
2 years ago
14

HURRYYYYYY !! A cube has an edge length of 9 centimeters.

Mathematics
1 answer:
CaHeK987 [17]2 years ago
5 0
The perimiter is 4 times 1 side
currently, it is 9 times 4 or 36

increased by 3
I think y mean times 3
so 9*3=27
new perimiter is 27*4=108

how much larger is it?
108-36=72

it is 72cm larger

it is the first answer
(it isn't cm² because that is for area and we are calculating perimiter)
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If cos(2/3x+20)°=sin(2x−10)°, find the acute angles of the corresponding right triangle.
adell [148]

Answer:

A = 40°

B = 50°

Step-by-step explanation:

If cos A = sin B, then A + B = 90

So, 2x/3 + 20  + 2x - 10 = 90

      2x + 60 + 6x - 30 = 270

               8x + 30 = 270

                       8x = 240

                          x = 30

2x/3 + 20 = 60/3 + 20 = 20 + 20 = 40

2x - 10 = 2(30) - 10 = 60 - 10 = 50  or  90 - 40 = 50

       

7 0
3 years ago
a cone with a radius of 3” has a total area of 24pie square inches. Find the volume of the cone. 12pie, 24 pie or 15 pie
Ratling [72]

Answer:

12\pi (inches)^{2}

Step-by-step explanation:

Given:

radius of cone = 3 inch

Total area of cone = 24\pi (inch)^{2}

Find the volume of the cone?

We know the area of cone = \pi r(r+s) -------(1)

Where r = radius

Ans s = side of the cone

Put the area value in equation 1

24\pi=\pi r(r+s) -------(1)

\frac{24\pi }{\pi r} =r+s

\frac{24}{ r}-r =s

Put r value in above equation.

s =\frac{24}{ 3}-3

s=8-3

s=5

The side s = 5 inches

We know the side of the cone formula

s^{2}=r^{2}+ h^{2}

h^{2}=s^{2}- r^{2}

Put r and s value in above equation.

h^{2}=5^{2}- 3^{2}

r^{2} = 25-9

r^{2} = 16

r = 4

The volume of cone is

V = \frac{1}{3} \pi r^{2} h

Put r and h value in above equation.

V = \frac{1}{3} \pi (3)^{2}\times 4

V = 12\pi (inches)^{2}

The Volume of the cone is 12\pi (inches)^{2}

7 0
3 years ago
What is 30 + 1/8 as a mixed number
Usimov [2.4K]
If you mean as a decimal, it's 30.125.
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3 years ago
Jamal bikes 5 miles in 20 minutes, or of an
anyanavicka [17]
Jamal would bike further in
5 0
2 years ago
The mean sat verbal score is 486, with a standard deviation of 95. use the empirical rule to determine what percent of the score
Pavel [41]
Find the z-scores for the two scores in the given interval.

z=\frac{x-\mu}{\sigma}

For the score x =391, z=\frac{391-486}{95}=\frac{-95}{95}=-1.

For the score x = 486, z=\frac{486-486}{95}=0

Now you want the area (proportion of data) under the normal distribution from z = -1 to z = 0. The Empirical Rule says that 68% of the data falls between z = -1 to z = 1. But the curve is symmetrical around the vertical axis at z = 0, so the answer you want is HALF of 68%.

8 0
3 years ago
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