<h3>Amount earned after 5 years is $ 9030.5561</h3>
<em><u>Solution:</u></em>
<em><u>The formula for compound interest, including principal sum, is:</u></em>
![A = p(1+\frac{r}{n})^{nt}](https://tex.z-dn.net/?f=A%20%3D%20p%281%2B%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D)
A = the future value of the investment including interest
P = the principal investment amount
r = the annual interest rate in decimal
n = the number of times that interest is compounded per unit t
t = the time the money is invested
From given,
p = 5000
t = 5 years
![r = 12 \% = \frac{12}{100} = 0.12](https://tex.z-dn.net/?f=r%20%3D%2012%20%5C%25%20%3D%20%5Cfrac%7B12%7D%7B100%7D%20%3D%200.12)
<em><u>n = 4 ( since interest is compounded quarterly )</u></em>
<em><u>Substituting the values we get,</u></em>
![A = 5000(1+\frac{0.12}{4})^{4 \times 5}\\\\A = 5000(1+0.03)^{20}\\\\A = 5000 \times 1.03^{20}\\\\A = 5000 \times 1.806111\\\\A = 9030.5561](https://tex.z-dn.net/?f=A%20%3D%205000%281%2B%5Cfrac%7B0.12%7D%7B4%7D%29%5E%7B4%20%5Ctimes%205%7D%5C%5C%5C%5CA%20%3D%205000%281%2B0.03%29%5E%7B20%7D%5C%5C%5C%5CA%20%3D%205000%20%5Ctimes%201.03%5E%7B20%7D%5C%5C%5C%5CA%20%3D%205000%20%5Ctimes%201.806111%5C%5C%5C%5CA%20%3D%209030.5561)
Thus amount earned after 5 years is $ 9030.5561
Answer:
it shows commutative property
Answer:
$1.44
Step-by-step explanation:
<u>Store A:</u>
12 bottles of water for $3.36
Then
48 bottles of water for
(48 bottles is 4 times greater than 12 bottles)
<u>Store B:</u>
24 bottles of water for $6.00
Then
48 bottles of water for
(48 bottles is twice greater than 24 bottles)
<u>Difference:</u>
![\$13.44-\$12=\$1.44](https://tex.z-dn.net/?f=%5C%2413.44-%5C%2412%3D%5C%241.44)
Answer:
Step-by-step explanation:
Because it is a square root