So we know that this amount of atoms is Avogadro's number - the number of atoms in 1 mole of a substance.
So then, using dimensional analysis, we can find the mass, in grams, of potassium.
First we must find the molar weight of potassium as found on the periodic table: 39.098g/mol
Then we can solve directly for mass:
Therefore, the amount of atoms you have given, in terms of mass, will equal 39.098g - if the answer requires significant figures, then the mass would be 39.1g of potassium.
Answer : There are basically three subatomic particles that exists; namely proton, neutron and electron.
Please refer the attached chart for the complete comparison.
- Protons are observed to be found in the nucleus of the atom. Which appears at the tiny, dense region at the center of the atom. They have a positive electrical charge of one (+1) and a mass of 1 atomic mass unit (amu).
- Neutrons exists in atoms of all elements they have neutrons located in their nucleus. Unlike protons and electrons, which are electrically charged, neutrons do not have any charge they are found to be electrically neutral. The mass of a neutron is slightly greater than the mass of a proton, which is 1 atomic mass unit (amu) .
- Electron are fundamental particles which does not consist of smaller particles. They are a type of fundamental particles called leptons. All leptons have an electric charge of −1 or 0 . Electrons are observed to be extremely small. The mass of an electron is only about 1/2000 the mass of a proton or neutron, so electrons contribute virtually nothing to the total mass of an atom. Electrons have an electric charge of −1 , which is equal but opposite to the charge of a proton, which is +1 . All atoms have the same number of electrons as protons, so the positive and negative charges "cancel out", making atoms electrically neutral.
Answer:
The uncertainty due to the equipment on chemistry equipment is equal to +-1/2 of the smallest unit marked in your equipment; in this case you have a pipette and its sameelst mark is 0.1 mL, so the uncertainty will be 0.05 mL. If you divide 0.05 mL / 3.2 mL and multiply it by 100 you get 1.56% of uncertainty if you measure 3.2 mL, so it will be proper to report the measurement and also the uncertainty.
On the cumulative Report, it would be much easier to read for the patients if the ranges in parentheses were tabbed over from the actual result instead of printing directly one space after the result.