Answer:
There isn't any picture for me to see
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Explanation:
Since
21.2 g H2O was produced, the amount of oxygen that reacted can be obtained
using stoichiometry. The balanced equation was given: 2H₂ + O₂ → 2H₂O and
the molar masses of the relevant species are also listed below. Thus, the
following equation is used to determine the amount of oxygen consumed.
Molar mass of H2O = 18
g/mol
Molar mass of O2 = 32
g/mol
21.2 g H20 x 1 mol
H2O/ 18 g H2O x 1 mol O2/ 2 mol H2O x 32 g O2/ 1 mol O2 = 18.8444 g O2
<span>We then determine that
18.84 g of O2 reacted to form 21.2 g H2O based on stoichiometry. It is
important to note that we do not need to consider the amount of H2 since we can
derive the amount of O2 from the product. Additionally, the amount of H2 is in
excess in the reaction.</span>
Answer:
![115.625^{\circ}\text{F}](https://tex.z-dn.net/?f=115.625%5E%7B%5Ccirc%7D%5Ctext%7BF%7D)
Explanation:
= First mass of water = 12 oz
= Second mass of water = 20 oz
= Temperature difference of the solution with respect to the first mass of water =
= Temperature difference of the solution with respect to the second mass of water = ![(T-75)^{\circ}\text{F}](https://tex.z-dn.net/?f=%28T-75%29%5E%7B%5Ccirc%7D%5Ctext%7BF%7D)
c = Specific heat of water
As heat gain and loss in the system is equal we have
![m_1c\Delta T_1=m_2c\Delta T_2\\\Rightarrow m_1\Delta T_1=m_2\Delta T_2\\\Rightarrow 12(T-75)=20(140-T)\\\Rightarrow 12T-900=2800-20T\\\Rightarrow 12T+20T=2800+900\\\Rightarrow 32T=3700\\\Rightarrow T=\dfrac{3700}{32}\\\Rightarrow T=115.625^{\circ}\text{F}](https://tex.z-dn.net/?f=m_1c%5CDelta%20T_1%3Dm_2c%5CDelta%20T_2%5C%5C%5CRightarrow%20m_1%5CDelta%20T_1%3Dm_2%5CDelta%20T_2%5C%5C%5CRightarrow%2012%28T-75%29%3D20%28140-T%29%5C%5C%5CRightarrow%2012T-900%3D2800-20T%5C%5C%5CRightarrow%2012T%2B20T%3D2800%2B900%5C%5C%5CRightarrow%2032T%3D3700%5C%5C%5CRightarrow%20T%3D%5Cdfrac%7B3700%7D%7B32%7D%5C%5C%5CRightarrow%20T%3D115.625%5E%7B%5Ccirc%7D%5Ctext%7BF%7D)
The final temperature of the solution is
.
The following aqueous solutions represents good buffer systems:
- 0.22 M acetic acid + 0.15 M potassium acetate
- 0.29 M ammonium nitrate + 0.32 M ammonia
<h3>What is a buffer?</h3>
A buffer is a solution used to stabilize the pH (acidity) of a liquid.
A good buffer system is generally known to contain close or equal concentrations of a weak acid and its conjugate base.
Based on the above explanation, the following represents a good buffer system as they are between their weak acid and conjugate base:
- 0.22 M acetic acid + 0.15 M potassium acetate
- 0.29 M ammonium nitrate + 0.32 M ammonia
Learn more about buffer at: brainly.com/question/22821585
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