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musickatia [10]
3 years ago
5

Carol buys a house for £234 900

Mathematics
2 answers:
VLD [36.1K]3 years ago
5 0

Answer: The solution would be like this for this specific problem:

Given:

Total amount of the house = £234,900

 

Find:

Amount of deposit paid = ?

 

So first, we divide the total amount of the house by the percent of deposit that Carol paid.

= £234,900 / 10%

= £23,490

 

Another way to solve this is by converting the percent of the deposit into a decimal. We do this by dividing the percentage amount by 100.

= 10% / 100%

= 0.1

 

Next, we multiply the decimal equivalent of the percentage to the total amount of the house.

= £234,900 * 0.1

= £23,490

 

So, the amount of deposit that was paid by Carol is £23,490.

oksano4ka [1.4K]3 years ago
4 0

Answer:

£23 490

Step-by-step explanation:

10%×234 900

=£23 490

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a car travels 120 mi. a second car, travelling 10 mph faster than the first car, makes the same trip in 1 hr less time. find the
Murrr4er [49]

<span>Let x be the speed of the first car, then (x + 10) is the speed of the second car.

We can write the equation by the condition of the problem:
</span>
\frac{120}{x}- \frac{120}{x+10}=1 \\ 120(x+10)-120(x)=1(x)(x+10)   \\ 120x+1200-120x=x^2+10x \\ x^2+10x-1200=0 \\ D=b^2-4ac=10^2-4*1*(-1200) = 100+4800 = 4900 \\ x_{1,2}= \frac{-bб \sqrt{D} }{2a}  \\  \\ x_1= \frac{-10- \sqrt{4900} }{2}= \frac{-10-70}{2} = -\frac{80}{2}=-40 \ \  \ \O

x_2= \frac{-10+ \sqrt{4900} }{2}= \frac{-10+70}{2} = \frac{60}{2}=30  mph s<span>peed ​​of the first car
</span>
Then 30+10=40 mph speed ​​of the second car

Answer: 30mph and 40 mph.


<span>I hope this helps.</span>
8 0
4 years ago
Is 19_10 equal to 20_ 10
-Dominant- [34]
First lets write this out:-
 
            ?
19 - 10 = 20 - 10

Now lets solve:-

19 - 10 =9

   ?
9 = 20 - 10

20 - 10 = 10

9 ≠ 10

Since 9 does not equal 10:-

19 - 10 ≠ 20 - 10

<span>Hope I helped ya!! </span>
5 0
4 years ago
In a flight of 600 km, the speed of the aircraft was slowed down due to bad weather. The average speed of the trip was decreased
UkoKoshka [18]

The average speed would be 600 km/hr.

Step-by-step explanation:

Let the original speed be 'x'

Let the decreased speed be 'x-200'

Distance = 600 km

Time increased by 30 minutes

According to question, it becomes,

\dfrac{600}{x-200}-\dfrac{600}{x}=\dfrac{30}{60}\\\\\dfrac{x-(x-200)}{x^2-200x}=\dfrac{1}{2\times 600}\\\\\dfrac{200}{x^2-200x}=\dfrac{1}{1200}\\\\240000=x^2-200x\\\\x^2-200x-240000=0\\\\x=600,-400

So, The average speed would be 600 km/hr.

5 0
3 years ago
What are the eight related addition and subtraction equations for 48, 42, 6
Len [333]

Answer:

Many of these are just the same equation in different orders.

42 + 6 = 48

6 + 42 = 48

48 = 6 + 42

48 = 42 + 6

42 = 48 - 6

48 - 6 = 42

6 = 48 - 42

48 - 42 = 6


6 0
3 years ago
Solve for x: −5|x + 1| = 10
11Alexandr11 [23.1K]

Answer:

x=10

Step-by-step explanation:

6 0
3 years ago
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