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Anna35 [415]
2 years ago
7

Help meeeeeeeeeeeeeee

Mathematics
1 answer:
Basile [38]2 years ago
5 0

Answer:

ganu mama gi

Step-by-step explanation:

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Sue has 18 sweets. Tony also has 18 sweets. Sue gives Tony x sweets. Sue then eats 5 of her sweets. Tony then eats half of his s
Ede4ka [16]
Answer is below.........

6 0
3 years ago
Pls help and have a great day <333!!!!
nirvana33 [79]

Answer:

find the least common multiple for the denominator and multiply with the numerator

for the first one,

Step-by-step explanation:

the common multiple for 4 and 6 is 12

4×3=12

6×2=12

multiply the same numbers with the numerator

1×3=3

5×2=10

the answer is 3/12 and 10/12

8 0
3 years ago
Find an equation for the parabola with focus at (-5,-4) and vertex at (-5,-3)
sattari [20]

Answer:

(x+5)^{2}=-4(y+3)

Step-by-step explanation:

Given:

Focus point = (-5, -4)

Vertex point = (-5, -3)

We need to find the equation for the parabola.

Solution:

Since the x-coordinates of the vertex and focus are the same,

so this is a regular vertical parabola, where the x part is squared. Since the vertex is above the focus, this is a right-side down parabola and p is negative.

The vertex of this parabola is at (h, k) and the focus is at (h, k + p). So, directrix is y = k - p.

Substitute y = -4 and k = -3.

-4 = -3+p

p=-4+3

p=-1

So the standard form of the parabola is written as.

(x-h)^{2}=4p(y-k)

Substitute vertex (h, k) = (-5, -3) and p = -1 in the above standard form of the parabola.

So the standard form of the parabola is written as.

(x-(-5))^{2}=4(-1)(y-(-3))

(x+5)^{2}=-4(y+3)

Therefore, equation for the parabola with focus at (-5,-4) and vertex at (-5,-3)

(x+5)^{2}=-4(y+3)

7 0
3 years ago
How many strings can be formed by ordering the letters MISSISSIPPI which
Mazyrski [523]

Answer:

<em>1680 is the answer.</em>

Step-by-step explanation:

Here, we have 11 letters in the word <em>MISSISSIPPI.</em>

Repetition of letters:

M - 1 time

I - 4 times

S - 4 times

P - 2 times

As per question statement, we need a substring MISS in the resultant strings.

So, we need to treat MISS as one unit so that <em>MISS always comes together in all the strings</em>.

The resultant strings will look like:

<em>xxxxMISSxxx</em>

<em>xxMISSxxxxx</em>

<em>and so on.</em>

After we treat <em>MISS </em>as one unit, total letters = 8

Repetition of letters:

MISS - 1 time

I - 3 times

S - 2 times

P - 2 times

The formula for combination of letters with total of <em>n </em>letters:

\dfrac{n!}{p!q!r!}

where <em>p, q</em> and <em>r</em> are the number of times other letters are getting repeated.

<em>p = 3</em>

<em>q = 2</em>

<em>r = 2</em>

<em></em>

So, required number of strings that contain MISS as substring:

\dfrac{8!}{3!2!2!}\\\Rightarrow \dfrac{40320}{6\times 2 \times 2}\\\Rightarrow 1680

So, <em>1680 is the answer.</em>

3 0
3 years ago
PLEASE HELP SUPER EASY GRAPHING PROBLEM, WILL MARK U BRAINLIEST
Maksim231197 [3]

Answer:

Step-by-step explanation:

x- int

1/3x - 2/3 = 0

1/3x = 2/3

3(1/3x = 2/3)

x = 2

(2, 0)

y- int

y = 1/3(0) - 2/3

y = 0 - 2/3

y = -2/3

(0, -2/3)

4 0
3 years ago
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