Answer:
find the least common multiple for the denominator and multiply with the numerator
for the first one,
Step-by-step explanation:
the common multiple for 4 and 6 is 12
4×3=12
6×2=12
multiply the same numbers with the numerator
1×3=3
5×2=10
the answer is 3/12 and 10/12
Answer:

Step-by-step explanation:
Given:
Focus point = (-5, -4)
Vertex point = (-5, -3)
We need to find the equation for the parabola.
Solution:
Since the x-coordinates of the vertex and focus are the same,
so this is a regular vertical parabola, where the x part is squared. Since the vertex is above the focus, this is a right-side down parabola and p is negative.
The vertex of this parabola is at (h, k) and the focus is at (h, k + p). So, directrix is y = k - p.
Substitute y = -4 and k = -3.



So the standard form of the parabola is written as.

Substitute vertex (h, k) = (-5, -3) and p = -1 in the above standard form of the parabola.
So the standard form of the parabola is written as.


Therefore, equation for the parabola with focus at (-5,-4) and vertex at (-5,-3)

Answer:
<em>1680 is the answer.</em>
Step-by-step explanation:
Here, we have 11 letters in the word <em>MISSISSIPPI.</em>
Repetition of letters:
M - 1 time
I - 4 times
S - 4 times
P - 2 times
As per question statement, we need a substring MISS in the resultant strings.
So, we need to treat MISS as one unit so that <em>MISS always comes together in all the strings</em>.
The resultant strings will look like:
<em>xxxxMISSxxx</em>
<em>xxMISSxxxxx</em>
<em>and so on.</em>
After we treat <em>MISS </em>as one unit, total letters = 8
Repetition of letters:
MISS - 1 time
I - 3 times
S - 2 times
P - 2 times
The formula for combination of letters with total of <em>n </em>letters:

where <em>p, q</em> and <em>r</em> are the number of times other letters are getting repeated.
<em>p = 3</em>
<em>q = 2</em>
<em>r = 2</em>
<em></em>
So, required number of strings that contain MISS as substring:

So, <em>1680 is the answer.</em>
Answer:
Step-by-step explanation:
x- int
1/3x - 2/3 = 0
1/3x = 2/3
3(1/3x = 2/3)
x = 2
(2, 0)
y- int
y = 1/3(0) - 2/3
y = 0 - 2/3
y = -2/3
(0, -2/3)