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malfutka [58]
3 years ago
12

How to solve in slope intercept form of the equation of the line through each pair of points?

Mathematics
1 answer:
den301095 [7]3 years ago
4 0
Let the points be (p,q) and (r,s).
The slope is (s-q)/(r-p). The equation is y-s=(s-q)(x-r)/(r-p).
This can be written (y-s)(r-p)=(s-q)(x-r).
y(r-p)-s(r-p)=x(s-q)-r(s-q); y(r-p)=x(s-q)+rs-ps-rs+qr; y=x(s-q)/(r-p)+(qr-ps)/(r-p).
Note that r cannot be equal to p in this standard form. If r=p we have a vertical line x=p.
If q=s we have the horizontal line y=q.
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4x/9=5/27 what is the value of x
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Now multiply both sides by 27 to give
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Now divide both sides by 108 to give
x = 45/108
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What is the measure of _RVE?
marysya [2.9K]

Answer:

D. 45

Step-by-step explanation:

<u>All angles</u><u> </u><u>h</u><u>a</u><u>v</u><u>e</u><u> </u><u>t</u><u>o</u><u> = 180°</u>

60 + 75 + <RVE = 180°

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180 - 135 = <u>4</u><u>5</u><u>°</u><u> </u><u>R</u><u>V</u><u>E</u>

<u>R</u><u>V</u><u>E</u><u> </u><u>=</u><u> </u><u>4</u><u>5</u><u>°</u>

<u>A</u><u>n</u><u>o</u><u>t</u><u>h</u><u>e</u><u>r</u><u> </u><u>w</u><u>a</u><u>y</u><u> </u><u>t</u><u>o</u><u> </u><u>c</u><u>h</u><u>e</u><u>c</u><u>k</u><u> </u><u>y</u><u>o</u><u>u</u><u>r</u><u> </u><u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>:</u>

Add all of the angles, and it should equal 180°

60 + 75 + 45 = 180°

Correct!

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