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malfutka [58]
3 years ago
12

How to solve in slope intercept form of the equation of the line through each pair of points?

Mathematics
1 answer:
den301095 [7]3 years ago
4 0
Let the points be (p,q) and (r,s).
The slope is (s-q)/(r-p). The equation is y-s=(s-q)(x-r)/(r-p).
This can be written (y-s)(r-p)=(s-q)(x-r).
y(r-p)-s(r-p)=x(s-q)-r(s-q); y(r-p)=x(s-q)+rs-ps-rs+qr; y=x(s-q)/(r-p)+(qr-ps)/(r-p).
Note that r cannot be equal to p in this standard form. If r=p we have a vertical line x=p.
If q=s we have the horizontal line y=q.
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f(x)=3x^(4)-5x^(3)-5x^(2)+5x+2 The number 3 is an upper bound for the set of roots of this polynomial function True or False
Leona [35]

Answer: TRUE

Step-by-step explanation: The number 3 is an upper bound because use 3 as a multiplyer of each bcoefficient of the polynomial and at each multiple,subtract the next coefficient from it. if all result after subtraction show positive, then the number used is an upper bound. This method is known as the synthetic division.

3        3      -5     -5        5         2

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3 years ago
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How much do u need to subtract from 41/6 to make 6
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3 years ago
Find the probability that a point is chosen randomly inside the rectangle is in each given shape...
Arlecino [84]

By taking the quotients between the areas, we see that:

  • a) P = 0.275
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<h3>How to find the probabilities?</h3>

First we need to find the areas of the 3 shapes.

For the triangle, the area is:

T = 3*5/2 = 7.5

For the blue square, the area is:

S = 3*3 = 9

For the rectangle, the area is:

R = 10*6 = 60

Now, what is the probability that a random point lies on the triangle or in the square?

It is equal to the quotient between the areas of the two shapes and the total area of the rectangle, this is:

P= (7.5 + 9)/60 = 0.275

b) The area of the rectangle that is not the square is:

A = 60 - 9 = 51

Then the probability of not landing on the square is:

P' = 51/60 = 0.85

If you want to learn more about probability:

brainly.com/question/25870256

#SPJ1

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