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Lena [83]
2 years ago
12

Hilary's Horse Hideaway is buying dirt to fill their circular training area. The training circle is 28 feet across. What is the

area of the training arena?
Show your work for finding area of arena.

The cost for dirt is $5.75 per foot. How much money will it cost to create this training area?

Show your work for finding cost of dirt.
Mathematics
1 answer:
AnnZ [28]2 years ago
5 0

Answer:

A = 615.75

cost = $107.08

Step-by-step explanation:

the training area = (28/2)^2*pi

training area = 615.75 square feet

615.75/5.75 = 107.08

$107.08

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Find the surface area of the composite figure.
taurus [48]

Answer:

surface area is 39

Step-by-step explanation:

add the areas of each geometric figure making up the composite 3D figure.

first 3D figure

2+2+6+6

=16---eq 1

from third 3D figure

4+4+10+5

= 23

from 1 and 2

16+23

= 39

may be!! I'm not sure bout this answer

3 0
3 years ago
please let us to do with it and it was the only one that I can get the best way for you and I am a bit more than one person who
Lelechka [254]
Inside, Lighthouse, Overboard (If You Can go Diagonal) Outback, Outdoors
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8 0
4 years ago
A population has a mean of 200 and a standard deviation of 50. Suppose a sample of size 100 is selected and x is used to estimat
zmey [24]

Answer:

a) 0.6426 = 64.26% probability that the sample mean will be within +/- 5 of the population mean.

b) 0.9544 = 95.44% probability that the sample mean will be within +/- 10 of the population mean.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 200, \sigma = 50, n = 100, s = \frac{50}{\sqrt{100}} = 5

a. What is the probability that the sample mean will be within +/- 5 of the population mean (to 4 decimals)?

This is the pvalue of Z when X = 200 + 5 = 205 subtracted by the pvalue of Z when X = 200 - 5 = 195.

Due to the Central Limit Theorem, Z is:

Z = \frac{X - \mu}{s}

X = 205

Z = \frac{X - \mu}{s}

Z = \frac{205 - 200}{5}

Z = 1

Z = 1 has a pvalue of 0.8413.

X = 195

Z = \frac{X - \mu}{s}

Z = \frac{195 - 200}{5}

Z = -1

Z = -1 has a pvalue of 0.1587.

0.8413 - 0.1587 = 0.6426

0.6426 = 64.26% probability that the sample mean will be within +/- 5 of the population mean.

b. What is the probability that the sample mean will be within +/- 10 of the population mean (to 4 decimals)?

This is the pvalue of Z when X = 210 subtracted by the pvalue of Z when X = 190.

X = 210

Z = \frac{X - \mu}{s}

Z = \frac{210 - 200}{5}

Z = 2

Z = 2 has a pvalue of 0.9772.

X = 195

Z = \frac{X - \mu}{s}

Z = \frac{190 - 200}{5}

Z = -2

Z = -2 has a pvalue of 0.0228.

0.9772 - 0.0228 = 0.9544

0.9544 = 95.44% probability that the sample mean will be within +/- 10 of the population mean.

7 0
3 years ago
1. What is the relationship of ratios and proportions? Give an example of a proportion.
shepuryov [24]
Ratio is the comparison of sizes of two quantities of the same unit. Proportions are the equality of two ratios. A/b =c/d
3 0
3 years ago
A scientist measures the water temperature in the Gulf at Gulfport on the fifteenth of each month. Her data is shown in the tabl
andrew-mc [135]
The average rate of change between March 15 and June 15 will be given by:
(82.4-66.8)/(6-3)
=15.6/3
=5.2° F per month

Answer: C
6 0
3 years ago
Read 2 more answers
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