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kap26 [50]
2 years ago
14

F(x)=−7x−1 find x if f(x) = -8

Mathematics
1 answer:
EastWind [94]2 years ago
3 0

Answer:

f(x) =  - 8 \\  \\  - 7x - 1 =  - 8 \\  \\  - 7x =  - 8 + 1 \\  \\  - 7x =  - 7 \\  \\ 7x = 7 \\  \\ x =  \frac{7}{7}  \\  \\ x = 1

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How can the quotient of powers law be used to show that a negative exponent is equivalent to the reciprocal
Kay [80]

Answer:Thus,  (-3)-4 = 1/(-3)4.

Step-by-step explanation:

Negative exponents have the following property:   n-m = 1/nm   OR   1/n-m = nm

So for  (-3)-4 ,  n= -3 and -m= -4 (or m= 4).

Thus,  (-3)-4 = 1/(-3)4.

8 0
1 year ago
The black graph is the graph of
bija089 [108]

Answer:

Who knows ask goku

Step-by-step explanation:

5 0
2 years ago
Describe at least two differences between constructing an inscribed regular hexagon and constructing an inscribed square.
liberstina [14]

Correct answer is A.

The diameter of the circle is used for the square construction, but the radius of the circle is used for the regular hexagon construction.

<h3>How to calculate the diameter?</h3>

If you know the radius of the circle, multiply by 2 to get the diameter. The radius is the distance from the center of the circle to the edge. For example, if the radius of a circle is 4 cm, then the diameter is 4 cm x 2 = 8 cm. If you know the circumference of the circle, divide by π to get the diameter.

<h3>Briefing:</h3>

The diameter of the circle is used for the square construction, but the radius of the circle is used for the regular hexagon construction which is A.

The diameter of the circle is used for the square as l=2r therefore corresponds to the diameter, while for a hexagon r=r being the radius of the circle.

To know more about Diameter visit:

brainly.com/question/5501950

#SPJ4

I understand that the question you are looking for is:

Describe at least two differences between constructing an inscribed regular hexagon and constructing an inscribed square.

A) The diameter of the circle is used for the square construction, but the radius of the circle is used for the regular hexagon construction.

B) The radius of the circle is used for the square construction, but the diameter of the circle is used for the regular hexagon construction.

C) The square will need two arcs along the circle, but the hexagon will need two arcs above and two arcs below the diameter of the circle.

D) The square will need six arcs along the circle, but the hexagon will need two arcs above and two arcs below the diameter of the circle.

7 0
1 year ago
What is -3 2/3 times (-2 1/4)?
butalik [34]
(-3 2/3) * (-2 1/4) ...turn to improper fractions
-11/3 * - 9/4 = ....now multiply straight across,and neg. x neg. = pos
99/12 reduces to 33/4 or 8 1/4
5 0
3 years ago
Rewrite in the form . Then find q(x) and r(x).
gizmo_the_mogwai [7]

Answer:

q(x)= 2x+5

r(x)=6

b(x)=x+4

Step-by-step explanation:

I have found what is missing in your question: Rewrite 2x^2+13x+26/x+4 in the form q(x)+r(x)/b(x).

First, we have to divide the polynomial  by x+4 and remember that is x times 2x.

By multiplying this we are going to get 2x^{2} + 8x and now we are doing separation of it and getting 2x^{2}  + 13x + 26 and getting 2x^{2}  + 13x + 26/ x + 4 = 2x^{2} +8x/x+4=5x+26/x+4=2x + 5x+26/x+4

Because 5 is showing x times 5 we are going to multiply (x + 4) with 5 and that is 5x + 20.

5x+26/x+4 = 5x + 20/x+4 = 6/ x+4=5 + 6/x+4

Now when we can get more simplified we are having:

2x^{2} +13+26/x+4=2x + 5= 6/x+4

3 0
3 years ago
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