If the sum of an integer and 7 more than the next consecutive integer is 66 then the integers are 29 and 30.
Given that the sum of an integer and 7 more than the next consecutive integer is 66.
Integer is a number that is written without a fraction component. It can be positive as well as negative.
let the first integer be x.
Consecutive integer will be x+1.
Sum of integer and 7 more than the next consecutive integer is 66.
Sum according to the given information=x+x+1+7
=2x+8
2x+8=66
2x=66-8
2x=58
x=58/2
x=29
Next integer=29+1-30.
Hence if the sum of an integer and 7 more than the next consecutive integer is 66 then the integers are 29 and 30.
Learn more about integers at brainly.com/question/17695139
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Answer:
0x+2y=22
Step-by-step explanation:
Set them equal to each other, (5x+4y=25)-(5x+2y=3). Distribute the negative into the right equation, (5x+4y=25)(-5x-2y=-3). Then combine like terms to get your answer.
Answer: The time is 20:15 on a military time clock.
Step-by-step explanation:
Answer:
Solution given
Sin Q=opposite/hypotenuse=28/29
<u>28/29</u><u> </u><u>is</u><u>. </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u><u>.</u><u />
Answer:
The height of the big cone is double the one in the small cone
h2 = 2h1
Step-by-step explanation:
Given that:
- The volume of the small cone: 5 cubic inches
- The volume of the big cone: 10 cubic inches
As we know, the volume of a cone is as following:
V = (1/3)*area of the base*height
If the base diameter are unchanged => area of the base of the two cones are unchanged and from the given information, the volume of the big cone is double the volume of the small cone. So the height of the big cone is double the one in the small cone
<=> h2 = 2h1
