90b + 150g > 500
0.35b + 2.50g < 15.00
what, is the question asking. These might help
Answer:
4/1/5=20 because when you divide by a fraction u keep change the divison into multiplaicton and flip the 1/5 to 5/1 so 4x5
Step-by-step explanation:
Answer:
The domain and the range of the function are, respectively:
![Dom\{f\} = [0\,m,5\,m]](https://tex.z-dn.net/?f=Dom%5C%7Bf%5C%7D%20%3D%20%5B0%5C%2Cm%2C5%5C%2Cm%5D)
![Ran\{f\} = [0\,m^{2}, 10\,m^{2}]](https://tex.z-dn.net/?f=Ran%5C%7Bf%5C%7D%20%3D%20%5B0%5C%2Cm%5E%7B2%7D%2C%2010%5C%2Cm%5E%7B2%7D%5D)
Step-by-step explanation:
Jina represented a function by a graphic approach, where the length, measured in meters, is the domain of the function, whereas the area, measured in square meters, is its range.
Answer:
Both A and B
Step-by-step explanation:
For functions you are just trying to make sure all the x's are different.
So let's look at A: The x's there are all different so it is a function
Now let's look at B: The x's there are all different so it is a function.
Both A and B
Answer:
(1) The sum of the lengths of the edges of the cube is 36.
A cube has 12 equal edges. Sum = 36. Length of each edge = 36/12 = 3
Volume = 3*3*3 = 27
(2) The surface area of the cube is 54.
A cube has 6 identical faces. Area of each face = s^2 (s is the length of the side)
6s^2 = 54
s = 3
Volume = 3*3*3 = 27
Step-by-step explanation:
All you need to uniquely define a cube is any one measurement - length of a side/edge, area of a surface, volume etc. If you have any one of them, you can uniquely determine the others. So each statement alone is sufficient here.
To show how,
(1) The sum of the lengths of the edges of the cube is 36.
A cube has 12 equal edges. Sum = 36. Length of each edge = 36/12 = 3
Volume = 3*3*3 = 27
(2) The surface area of the cube is 54.
A cube has 6 identical faces. Area of each face = s^2 (s is the length of the side)
6s^2 = 54
s = 3
Volume = 3*3*3 = 27
