Answer:
a) Micheal's present age = 8 years old
b) The sum of their ages in 6 years time = 63 years.
Step-by-step explanation:
From the above question, we know that
Rui feng is 3 years old
We are told that
• Michael is 5 years old than Rui feng
Micheal's present age is calculated as:
= 5 + Rui feng's age
= 5 + 3 = 8 years
• Vishal is thrice as old as Micheal
Vishal's present age is calculated as
= 3(Micheal age)
= 3(8)
= 24 years.
The sum of their ages in six years time
= ( 3 + 6) +( 8 + 6) + ( 24 + 6)
= 18 + 15 + 30
= 63 years
Therefore, a) Micheal's present age = 8 years old
b) The sum of their ages in 6 years time = 63 years.
it would be C i think hope this helps
Given a number n, the addititive inverse is -n since n+(-n)=0. However
n+(-n) is the same as n-n which is 0 also.
SO adding the additive inverse it the same as subtracting
Using a system of equations, it is found that Peter had $48 at first.
<h3>What is a system of equations?</h3>
A system of equations is when two or more variables are related, and equations are built to find the values of each variable.
In this problem, the variables are:
- Variable x: Peter's money.
- Variable y: Henry's money.
The ratio of peters money to henrys money is 4 : 3, hence:
After Peter spent $12, they had the same amount, hence:
y = x - 12.
Then, replacing in the ratio:
4(x - 12) = 3x
x = 48.
More can be learned about a system of equations at brainly.com/question/24342899
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