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ivolga24 [154]
2 years ago
11

5. Give two equations that will cross at (3, 4)

Mathematics
1 answer:
Anton [14]2 years ago
6 0

Answer: 4x=3y, 8x=6y

Step-by-step explanation: We can use a simplified form of an equation for this specific problem, since a solution is (3,4), if you plugin 3 for x and 4 for y you get the same thing. Since 4 times 3 equals 3 times 4 you can call x as 4 and y as 3. You can simply multiply this by 2 for another equation since it doesn't affect the ratio. I hope this helps!

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How much air can the basketball<br> hold? With a radius of 3 inches. Round to the nearest hundredth.
choli [55]

Answer:

113.10 if you use the pi button

113.04 if you use 3.14

Step-by-step explanation:

We want to find the volume

V = 4/3  pi r^3

The radius is 3

V = 4/3 pi (3)^3

Using the pi button for pi

V = 113.09734

Rounding to the nearest hundredth

V = 113.10

If you use 3.14 for pi

V = 113.04

3 0
2 years ago
8. On Monday, 301 students went on a trip to the zoo. All 7 buses were filled and 7 students had to travel in
tankabanditka [31]

Answer:

42 Kids

Step-by-step explanation:

1st you have to subtract 7 form 301 so you get 294

2nd you divide 294 by 7 294/7

And you should get an answer of 42 Kids

5 0
3 years ago
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Can't figure out where to put the parentheses
Shtirlitz [24]
8 times 4 and 8 divided by 2 i think
8 0
3 years ago
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You and a partner tend 3 machines that run continuously. One prints 200 plastic bottles per hour, one prints 180 plastic bottles
Airida [17]
I dont know the answer im just here for points

5 0
3 years ago
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Please help me 33/2 + 3y/5 = 7y/10 + 15
8090 [49]

We are given with an equation in <em>variable y</em> and we need to solve for <em>y</em> . So , now let's start !!!

We are given with ;

{:\implies \quad \sf \dfrac{33}{2}+\dfrac{3y}{5}=\dfrac{7y}{10}+15}

Take LCM on both sides :

{:\implies \quad \sf \dfrac{165+6y}{10}=\dfrac{7y+150}{10}}

<em>Multiplying</em> both sides by <em>10</em> ;

{:\implies \quad \sf \cancel{10}\times \dfrac{165+6y}{\cancel{10}}=\cancel{10}\times \dfrac{7y+150}{\cancel{10}}}

{:\implies \quad \sf 165+6y=7y+150}

Can be <em>further written</em> as ;

{:\implies \quad \sf 7y+150=165+6y}

Transposing <em>6y </em>to<em> LHS</em> and <em>150</em> to<em> RHS </em>

{:\implies \quad \sf 7y-6y=165-150}

{:\implies \quad \bf \therefore \quad \underline{\underline{y=15}}}

8 0
2 years ago
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