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2 years ago

Find the perimeter of rectangle.

Mathematics

2 answers:

marishachu [46]2 years ago

8 0

Answer:

it depends on how big the rectangle is though...

Step-by-step explanation:

solniwko [45]2 years ago

5 0

Answer:

6x + 10

Step-by-step explanation:

Given,

Length ( l ) = 3x

Breadth ( b ) = 5

To find : Perimeter of the rectangle = ?

Formula : -

Perimeter of the rectangle = 2 ( l + b )

Perimeter of the rectangle

= 2 ( 3x + 5 )

= 2 ( 3x ) + 2 ( 5 )

= 6x + 10

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Let us analyze the following setting. You are given a circle of unit circumference. You pickkpoints on the circle independently

garik1379 [7]

Answer:

We have been given a unit circle which is cut at k different points to produce k different arcs. Now we can see firstly that the sum of lengths of all k arks is equal to the circumference:

$\small \sum_{i = 1}^{k} L_i= 2\pi$

Now consider the largest arc to have length \small l . And we represent all the other arcs to be some constant times this length.

we get :

$\small \sum_{i = 1}^{k} C_i.l = 2\pi$

where C(i) is a constant coefficient obviously between 0 and 1.

$\small \sum_{i = 1}^{k} C_i= 2\pi/l$

All that I want to say by using this step is that after we choose the largest length (or any length for that matter) the other fractions appear according to the above summation constraint. [This step may even be avoided depending on how much precaution you wanna take when deriving a relation.]

So since there is no bias, and \small l may come out to be any value from [0 , 2π] with equal probability, the expected value is then defined as just the average value of all the samples.

We already know the sum so it is easy to compute the average :

$\small L_{Exp} = \frac{2\pi}{k}$

7 0

2 years ago

A shape has 2 pairs of parallel sides and no right angles. What shape is it?

Flauer [41]

The answer is the Parallelogram

3 0

2 years ago

Read 2 more answers

HELP, I’M STUCK !

vaieri [72.5K]

Since P(X = x) = 0.3 for all 0 ≤ x ≤ α, we have

$\displaystyle\int_{-\infty}^\infty P(X=x)\,\mathrm dx=1\implies0.3\int_0^\alpha\mathrm dx=0.3\alpha=1\implies\alpha=\dfrac{10}3$

So,

$P(X>2) = \displaystyle\int_2^\infty P(X=x)\,\mathrm dx=0.3\int_2^{\frac{10}3}\mathrm dx$

$P(X>2)=0.3\left(\dfrac{10}3-2\right)=\boxed{\dfrac25}$

6 0

2 years ago

With a height of 68 in, Nelson was the shortest president of a particular club in the past century. The club presidents of the

Ivahew [28]

Answer:

a. The positive difference between Nelson's height and the population mean is: $\\ \lvert 68-70.7 \rvert = \lvert 70.7-68 \rvert\;in = 2.7\;in$ .

b. The difference found in part (a) is 1.174 standard deviations from the mean (without taking into account if the height is above or below the mean).

c. Nelson's z-score: $\\ z = -1.1739 \approx -1.174$ (Nelson's height is below the population's mean 1.174 standard deviations units).

d. Nelson's height is usual since $\\ -2 < -1.174 < 2$ .

Step-by-step explanation:

The key concept to answer this question is the z-score. A z-score "tells us" the distance from the population's mean of a raw score in standard deviation units. A positive value for a z-score indicates that the raw score is above the population mean, whereas a negative value tells us that the raw score is below the population mean. The formula to obtain this z-score is as follows:

$\\ z = \frac{x - \mu}{\sigma}$ [1]

Where

$\\ z$ is the z-score.

$\\ \mu$ is the population mean.

$\\ \sigma$ is the population standard deviation.

From the question, we have that:

Nelson's height is 68 in. In this case, the raw score is 68 in $\\ x = 68$ in.
$\\ \mu = 70.7$ in.
$\\ \sigma = 2.3$ in.

With all this information, we are ready to answer the next questions:

a. What is the positive difference between Nelson's height and the mean?

The positive difference between Nelson's height and the population mean is (taking the absolute value for this difference):

$\\ \lvert 68-70.7 \rvert = \lvert 70.7-68 \rvert\;in = 2.7\;in$ .

That is, the positive difference is 2.7 in.

b. How many standard deviations is that [the difference found in part (a)]?

To find how many standard deviations is that, we need to divide that difference by the population standard deviation. That is:

$\\ \frac{2.7\;in}{2.3\;in} \approx 1.1739 \approx 1.174$

In words, the difference found in part (a) is 1.174 standard deviations from the mean. Notice that we are not taking into account here if the raw score, x, is below or above the mean.

c. Convert Nelson's height to a z score.

Using formula [1], we have

$\\ z = \frac{x - \mu}{\sigma}$

$\\ z = \frac{68\;in - 70.7\;in}{2.3\;in}$

$\\ z = \frac{-2.7\;in}{2.3\;in}$

$\\ z = -1.1739 \approx -1.174$

This z-score "tells us" that Nelson's height is 1.174 standard deviations below the population mean (notice the negative symbol in the above result), i.e., Nelson's height is below the mean for heights in the club presidents of the past century 1.174 standard deviations units.

d. If we consider "usual" heights to be those that convert to z scores between minus2 and 2, is Nelson's height usual or unusual?

Carefully looking at Nelson's height, we notice that it is between those z-scores, because:

$\\ -2 < z_{Nelson} < 2$

$\\ -2 < -1.174 < 2$

Then, Nelson's height is usual according to that statement.

7 0

2 years ago

How do I do number 4

nikitadnepr [17]

Answer:

its 6.40

Step-by-step explanation:

you have to use the distance formula which is

$d=\sqrt(x2-x1)^{2} + (y2-y1)^2$

so points C is (-5,-1) and D is (0,3)

then you substitute the x

0--5=5^2

then

3--1+4^2=16

25+16=41

then square rout that and it equals 6.40

7 0

3 years ago